Breaking News: Grepper is joining You.com. Read the official announcement!

Valid Parentheses

Add Answer

CodeBlack reactor answered on January 24, 2022 Popularity 7/10 Helpfulness 1/10

answer Valid Parentheses

related valid parentheses

related Valid Parentheses

related Valid parentheses

related valid parentheses

related Valid Parentheses

related valid parentheses

related Valid Parentheses

Valid Parentheses

Comment

-1

class Solution {

    /**
     * @param String $s
     * @return Boolean
     */
    function isValid($s) {
        
    }
}

Popularity 7/10 Helpfulness 1/10 Language php

Source: Grepper

Tags: parentheses php

Link to this answer
Share Copy Link

Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Closely Related Answers

valid parentheses

Comment

let s = '([]{})()'

const isValid = function(s) {
    let stack = []
    let characters = '()[]{}'   // even, odd, even, odd, even, odd

    for (let i = 0; i < s.length; i++) {
        let index = characters.indexOf(s[i])

        if (index % 2 === 0) {
            stack.push(s[i])
        } else if (index % 2 !== 0 && stack[stack.length - 1] === characters[index - 1]) {
            stack.pop()
        } else {
            return false
        }

        console.log(stack)
    }

    return !stack.length
}


console.log(isValid(s))

// [Log]:
[ '(' ]
[ '(', '[' ]
[ '(' ]
[ '(', '{' ]
[ '(' ]
[]
[ '(' ]
[]
true

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: javascript j

Link to this answer
Share Copy Link

Contributed on Nov 27 2022

Mysterious Macaque

0 Answers Avg Quality 2/10

Valid Parentheses

Comment

class Solution:
    def isValid(self, s):
        if s == "":
            return True
        if len(s) < 2:
            return False

        pair_brkts = {
            "{" : "}",
            "(" : ")",
            "[" : "]"
            }
        stack = []

        for i in s:
            if i in pair_brkts:
                stack.append(i)                                #stack i(forward facing brackets) that also exists as keys in our pair_brkts dictionary)
                #print("forward facing brackets", stack)       #to see the contents of your stacked list 
            else:
                if len(stack) == 0 or pair_brkts[stack.pop()] != i:   #if stack list is empty or the value pair of last 
                                                                        #list item isnt same, return False, otherwise break out of loop
                    #print("backward facing brackets", stack)        #print to see whats left of your list after 
                                                                    #looping is over for all your i(i.e brackets)
                    return False
        if len(stack) > 0:                                          #if stack list is not empty at this point, return False, else return True
            return False
        return True

 
        

Task = Solution()
print("1. ", Task.isValid("({[()]})"))
print("2. ", Task.isValid("()[]{}"))
print("3. ", Task.isValid("(]"))

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: parentheses pare

Link to this answer
Share Copy Link

Contributed on May 18 2022

Kingsley Atuba

0 Answers Avg Quality 2/10

Valid parentheses

Comment

class Solution:
   def isValid (self, sequence: str):
       '''
       Function to pair if sequence contains valid parenthesis
       :param sequence: Sequence of brackets
       :return: True is sequence is valid else False
       '''
       stack = []
       opening = set('([{')
       closing = set(')]}')
       pair = {')' : '(' , ']' : '[' , '}' : '{'}
       for i in sequence :
           if i in opening :
               stack.append(i)
           if i in closing :
               if not stack :
                   return False
               elif stack.pop() != pair[i] :
                   return False
               else :
                   continue
       if not stack :
           return True
       else :
           return False

if __name__ == '__main__':
   sequence = '{[()]}'
   print(f'Is {sequence} valid ? : {Solution().isValid(sequence)}')
   sequence1 = '{[()]}{]{}}'
   print(f'Is {sequence1} valid ? : {Solution().isValid (sequence1)}')

Popularity 9/10 Helpfulness 3/10 Language python

Source: favtutor.com

Tags: parentheses pare

Link to this answer
Share Copy Link

Contributed on Jan 24 2022

Itchy Impala

0 Answers Avg Quality 2/10

valid parentheses

Comment

/*
	n = 3
    
    [ '()()()', '()(())', '(())()', '(()())', '((()))' ]
*/

const generateParenthesis = function (n) {
    const res = [];

    const dfs = function (left = n, right = n, combos = '') {
        if (combos.length === 2*n) {
            res.push(combos);
        }
        else if (left <= right) {
            if (left > 0) {
                dfs(left - 1, right, combos + '(');
            }

             if (right > 0) {
                dfs(left, right - 1, combos + ')');
            }
        }
    }

    dfs();

    return res;
}

console.log(generateParenthesis(3));

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

Link to this answer
Share Copy Link

Contributed on Nov 28 2023

Mysterious Macaque

0 Answers Avg Quality 2/10

valid parentheses

Comment

{ { } [ ] [ [ [ ] ] ] } is VALID expression
          [ [ [ ] ] ]    is VALID sub-expression
  { } [ ]                is VALID sub-expression

Popularity 9/10 Helpfulness 1/10 Language java

Source: leetcode.com

Tags: java

Link to this answer
Share Copy Link

Contributed on Mar 06 2022

Hugo Barcelos

0 Answers Avg Quality 2/10

Valid Parentheses

Comment


bool isValid(char * s){

}

Popularity 7/10 Helpfulness 1/10 Language c

Source: Grepper

Tags: c parentheses

Link to this answer
Share Copy Link

Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Valid Parentheses

Comment

function isValid(s: string): boolean {

};

Popularity 8/10 Helpfulness 1/10 Language typescript

Source: Grepper

Tags: parentheses pare

Link to this answer
Share Copy Link

Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

valid parentheses

Comment

Input: s = "()[]{}"
Output: true

Popularity 7/10 Helpfulness 1/10 Language javascript

Source: leetcode.com

Tags: javascript parentheses

Link to this answer
Share Copy Link

Contributed on Dec 11 2022

shivam chauhan

0 Answers Avg Quality 2/10

Valid Parentheses

Comment

import scala.collection.mutable.Stack

object ValidParentheses {
  def isValid(s: String): Boolean = {
    val stack = Stack[Char]()
    val map = Map(')' -> '(', '}' -> '{', ']' -> '[')

    for (char <- s) {
      if (map.contains(char)) {
        if (stack.isEmpty || stack.pop() != map(char))
          return false
      } else {
        stack.push(char)
      }
    }

    stack.isEmpty
  }

  def main(args: Array[String]): Unit = {
    // Example usage
    val input1 = "()[]{}" // Valid
    val input2 = "([)]"   // Invalid
    val input3 = "{[]}"   // Valid

    println(s"Is '$input1' valid? ${isValid(input1)}")
    println(s"Is '$input2' valid? ${isValid(input2)}")
    println(s"Is '$input3' valid? ${isValid(input3)}")
  }
}

Popularity 6/10 Helpfulness 1/10 Language scala

Source: chat.openai.com

Tags: parentheses scala

Link to this answer
Share Copy Link

Contributed on Sep 08 2023

Sumit Rawal

0 Answers Avg Quality 2/10

Valid Parentheses

Comment

-1

# @param {String} s
# @return {Boolean}
def is_valid(s)
    
end

Popularity 8/10 Helpfulness 1/10 Language ruby

Source: Grepper

Tags: parentheses ruby

Link to this answer
Share Copy Link

Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Valid Parentheses

Contents

More Related Answers

Valid Parentheses

Closely Related Answers

valid parentheses

Valid Parentheses

Valid parentheses

valid parentheses

valid parentheses

Valid Parentheses

Valid Parentheses

valid parentheses

Valid Parentheses

Valid Parentheses

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.