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std::future

Kevin Vincent answered on June 8, 2022 Popularity 6/10 Helpfulness 3/10

answer std::future

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std::future

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#include <iostream>
#include <future>
#include <thread>
 
int main()
{
    // future from a packaged_task
    std::packaged_task<int()> task([]{ return 7; }); // wrap the function
    std::future<int> f1 = task.get_future();  // get a future
    std::thread t(std::move(task)); // launch on a thread
 
    // future from an async()
    std::future<int> f2 = std::async(std::launch::async, []{ return 8; });
 
    // future from a promise
    std::promise<int> p;
    std::future<int> f3 = p.get_future();
    std::thread( [&p]{ p.set_value_at_thread_exit(9); }).detach();
 
    std::cout << "Waiting..." << std::flush;
    f1.wait();
    f2.wait();
    f3.wait();
    std::cout << "Done!\nResults are: "
              << f1.get() << ' ' << f2.get() << ' ' << f3.get() << '\n';
    t.join();
}

Popularity 6/10 Helpfulness 3/10 Language whatever

Source: en.cppreference.com

Tags: whatever

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Contributed on Aug 17 2022

Kevin Vincent

0 Answers Avg Quality 2/10

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#include <iostream>
#include <future>
#include <thread>

int main() {
    // 将一个返回值为7的 lambda 表达式封装到 task 中
    // std::packaged_task 的模板参数为要封装函数的类型
    std::packaged_task<int()> task([](){return 7;});
    // 获得 task 的期物
    std::future<int> result = task.get_future(); // 在一个线程中执行 task
    std::thread(std::move(task)).detach();
    std::cout << "waiting...";
    result.wait(); // 在此设置屏障，阻塞到期物的完成
    // 输出执行结果
    std::cout << "done!" << std:: endl << "future result is " << result.get() << std::endl;
    return 0;
}

Popularity 6/10 Helpfulness 2/10 Language cpp

Source: changkun.de

Tags: c++

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Contributed on Jun 08 2022

hokori

0 Answers Avg Quality 2/10

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