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longest substring without repeating characters

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Ryan Garcia answered on February 17, 2022 Popularity 10/10 Helpfulness 3/10

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longest substring without repeating characters

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// JavaScript Solution - Credit to @albertchanged on LC
// Sliding window implementation
var lengthOfLongestSubstring = function(s) {
  if (!s.length) return 0;
  
  let left = 0, right = 0;
  let maxLength = -Infinity;
  const set = new Set();

  while (right < s.length) {
    // If s[right] has not been seen yet
    if (!set.has(s[right])) {
      // Add it to the set
      set.add(s[right]);
      // Increase size of window to right
      right++;
      // Update maxLength; set size represents length of unique substring
      maxLength = Math.max(maxLength, set.size);
    } else {
      // We've seen s[right] so we need to shrink the window
      // Delete s[left] from set
      set.delete(s[left]);
      // Shrink window from left
      left++;
    }
  }

  return maxLength;
}

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript longest-substring

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Contributed on Aug 21 2022

Ryan Garcia

0 Answers Avg Quality 2/10

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longest substring without repeating characters

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/**
 * @param {string} s
 * @return {number}
 */
var lengthOfLongestSubstring = function(s) {
    if (!s.length) return 0

    let left = 0, right = 0
    let maxLength = -Infinity
    const hashSet = {}
    const len = s.length

    while(right < len){
        if (hashSet.hasOwnProperty(s[right])){
            if (hashSet[s[right]] >= left){
                left = hashSet[s[right]]+1
            }
        }
            const lenn = right-left+1
            maxLength = Math.max(lenn, maxLength)
            hashSet[s[right]] = right
            right++
        
    }
    return maxLength

};

Popularity 9/10 Helpfulness 3/10 Language javascript

Source: leetcode.com

Tags: javascript j

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Contributed on Jul 31 2024

Adventurous Alligator

0 Answers Avg Quality 2/10

Longest Substring Without Repeating Characters

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/*
    Javascript Solution - With Better Performance
    Methods used in this algorithm are:
    1. Two Pointer Technique
    2. Sliding Window Technique
    3. Hash Map

    Time complexity: O(N)
    Space complexity: O(N),
    If the string does not contain repeated characters, 
    then the hash map will contain N characters.
*/

const s = "sdtvtsgh"

const lengthOfLongestSubstring = function(s) {
    let max_length = 0
    let map = {}
    let l = 0

    for (let r = 0; r < s.length; r++) {
        if (map.hasOwnProperty(s[r])) {
            const collision_index = map[s[r]]

            if (collision_index >= l) {
                l = collision_index + 1
            }

            delete map[s[collision_index]]
        }

        if (!map.hasOwnProperty(s[r])) {
            map[s[r]] = r
        }

        if (max_length < (r + 1) - l) {
            max_length = (r + 1) - l
        }

        console.log(map, ':   (', r + 1, '-', l, ')')
    }

    return max_length
}


console.log(lengthOfLongestSubstring(s))

// [Log]:
{ s: 0 } :   ( 1 - 0 )
{ s: 0, d: 1 } :   ( 2 - 0 )
{ s: 0, d: 1, t: 2 } :   ( 3 - 0 )
{ s: 0, d: 1, t: 2, v: 3 } :   ( 4 - 0 )
{ s: 0, d: 1, v: 3, t: 4 } :   ( 5 - 3 )
{ d: 1, v: 3, t: 4, s: 5 } :   ( 6 - 3 )
{ d: 1, v: 3, t: 4, s: 5, g: 6 } :   ( 7 - 3 )
{ d: 1, v: 3, t: 4, s: 5, g: 6, h: 7 } :   ( 8 - 3 )

max_length = 5

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Aug 21 2022

Mysterious Macaque

0 Answers Avg Quality 2/10

3. Longest Substring Without Repeating Characters

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import java.io.*;
 
class GFG {
    public static int longestUniqueSubsttr(String str)
    {
        String test = "";
 
        // Result
        int maxLength = -1;
 
        // Return zero if string is empty
        if (str.isEmpty()) {
            return 0;
        }
        // Return one if string length is one
        else if (str.length() == 1) {
            return 1;
        }
        for (char c : str.toCharArray()) {
            String current = String.valueOf(c);
 
            // If string already contains the character
            // Then substring after repeating character
            if (test.contains(current)) {
                test = test.substring(test.indexOf(current)
                                      + 1);
            }
            test = test + String.valueOf(c);
            maxLength = Math.max(test.length(), maxLength);
        }
 
        return maxLength;
    }
 
    // Driver code
    public static void main(String[] args)
    {
        String str = "geeksforgeeks";
        System.out.println("The input string is " + str);
 
        int len = longestUniqueSubsttr(str);
        System.out.println("The length of the longest "
                           + "non-repeating character "
                           + "substring is " + len);
    }
}
 
// This code is contributed by Alex Bennet

Popularity 10/10 Helpfulness 3/10 Language java

Source: www.geeksforgeeks.org

Tags: java

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Contributed on Feb 17 2022

Manav Sarkar

0 Answers Avg Quality 2/10

longest substring without repeating characters

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class Solution {
    public int lengthOfLongestSubstring(String s) {int max=0;
        HashMap<Character,Integer>hm=new HashMap<>();
        for(int i=0,j=0;i<s.length();i++){
            if(hm.containsKey(s.charAt(i))){
                j=Math.max(j,hm.get(s.charAt(i))+1);
            }
            hm.put(s.charAt(i),i);
            max=Math.max(max,i-j+1);
        }
        return max;
        
    }
}

Popularity 10/10 Helpfulness 3/10 Language whatever

Source: Grepper

Tags: longest-substring longest-substrin

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Contributed on Aug 22 2022

Nasty Nightingale

0 Answers Avg Quality 2/10

longest substring without repeating characters

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public class Solution 
{
    public int LengthOfLongestSubstring(string str) 
    {
        var dict = new Dictionary<char, int>();
        var max = 0;
        int start = 0;
        for (int i = 0; i < str.Length; i++)
        {
            var x = str[i];
            if (!dict.ContainsKey(x))
            {
                dict.Add(x, 1);
            }
            else
            {
                dict[x] += 1;
                while (start <= i && dict.ContainsKey(str[start]) && dict[x] > 1)
                {
                    dict[str[start]]--;
                    if (dict[str[start]] == 0)
                        dict.Remove(str[start]);
                    start++;
                }
            }
            max = Math.Max(max, i - start + 1);
        }
        return max;
    }
}

Popularity 10/10 Helpfulness 3/10 Language csharp

Source: leetcode.com

Tags: c# c

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Contributed on Jun 10 2022

PrashantUnity

0 Answers Avg Quality 2/10

Longest Substring Without Repeating Characters

Comment

/*
  Given a string s, find the length of the longest substring (A substring is 
  a contiguous non-empty sequence of characters within a string.) 
  without repeating characters.

  Example 1:
  Input: s = "abcabcbb"
  Output: 3
  Explanation: The answer is "abc", with the length of 3.
  
  Example 2:
  Input: s = "bbbbb"
  Output: 1
  Explanation: The answer is "b", with the length of 1.
  
  Example 3:
  Input: s = "pwwkew"
  Output: 3
  Explanation: The answer is "wke", with the length of 3.
  Notice that the answer must be a substring, "pwke" is a subsequence and 
  not a substring.
*/

   const longestStr = s => {
    if(s.length < 2) return s.length

    let [left, right, partial, curIdx, finalLength] = 
        [0, s.length, new Set(), 0, -Infinity]

    while (left < right) {
        partial.add(s[left])

        const curChar = s[left+1]

        // Base case to exit loop early
        if (finalLength > (right - curIdx)) break

        if (partial.has(curChar)) {
            curIdx += 1
            left = curIdx

            partial.size > finalLength ? finalLength = partial.size : null
            partial.clear()
        }else left++

        left === right ? partial.size > finalLength ? 
          finalLength = partial.size : null : null

    }

    return finalLength
  }

  const s = "abcabcbb" // 3
  const res = longestStr(s)
  console.log(res)
    
  /*
	Time Complexity: O(n) (average case)
	Space Complexity: O(n)  
  */

// With love @kouqhar

Popularity 3/10 Helpfulness 2/10 Language javascript

Source: www.linkedin.com

Tags: javascript longest-substring

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Contributed on Nov 07 2024

kouqhar

0 Answers Avg Quality 2/10

json to dart

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class DataDTO {
  String? _name;
  String? _gender;
  int? _age;
  Address? _address;
  List<PhoneNumber>? _phoneNumber;

  DataDTO(
      {String? name,
      String? gender,
      int? age,
      Address? address,
      List<PhoneNumber>? phoneNumber}) {
    if (name != null) {
      this._name = name;
    }
    if (gender != null) {
      this._gender = gender;
    }
    if (age != null) {
      this._age = age;
    }
    if (address != null) {
      this._address = address;
    }
    if (phoneNumber != null) {
      this._phoneNumber = phoneNumber;
    }
  }

  String? get name => _name;
  set name(String? name) => _name = name;
  String? get gender => _gender;
  set gender(String? gender) => _gender = gender;
  int? get age => _age;
  set age(int? age) => _age = age;
  Address? get address => _address;
  set address(Address? address) => _address = address;
  List<PhoneNumber>? get phoneNumber => _phoneNumber;
  set phoneNumber(List<PhoneNumber>? phoneNumber) => _phoneNumber = phoneNumber;

  DataDTO.fromJson(Map<String, dynamic> json) {
    _name = json['name'];
    _gender = json['gender'];
    _age = json['age'];
    _address =
        json['address'] != null ? new Address.fromJson(json['address']) : null;
    if (json['phoneNumber'] != null) {
      _phoneNumber = <PhoneNumber>[];
      json['phoneNumber'].forEach((v) {
        _phoneNumber!.add(new PhoneNumber.fromJson(v));
      });
    }
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['name'] = this._name;
    data['gender'] = this._gender;
    data['age'] = this._age;
    if (this._address != null) {
      data['address'] = this._address!.toJson();
    }
    if (this._phoneNumber != null) {
      data['phoneNumber'] = this._phoneNumber!.map((v) => v.toJson()).toList();
    }
    return data;
  }
}

class Address {
  String? _street;
  String? _city;
  String? _state;
  String? _postalCode;

  Address({String? street, String? city, String? state, String? postalCode}) {
    if (street != null) {
      this._street = street;
    }
    if (city != null) {
      this._city = city;
    }
    if (state != null) {
      this._state = state;
    }
    if (postalCode != null) {
      this._postalCode = postalCode;
    }
  }

  String? get street => _street;
  set street(String? street) => _street = street;
  String? get city => _city;
  set city(String? city) => _city = city;
  String? get state => _state;
  set state(String? state) => _state = state;
  String? get postalCode => _postalCode;
  set postalCode(String? postalCode) => _postalCode = postalCode;

  Address.fromJson(Map<String, dynamic> json) {
    _street = json['street'];
    _city = json['city'];
    _state = json['state'];
    _postalCode = json['postalCode'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['street'] = this._street;
    data['city'] = this._city;
    data['state'] = this._state;
    data['postalCode'] = this._postalCode;
    return data;
  }
}

class PhoneNumber {
  String? _type;
  String? _number;

  PhoneNumber({String? type, String? number}) {
    if (type != null) {
      this._type = type;
    }
    if (number != null) {
      this._number = number;
    }
  }

  String? get type => _type;
  set type(String? type) => _type = type;
  String? get number => _number;
  set number(String? number) => _number = number;

  PhoneNumber.fromJson(Map<String, dynamic> json) {
    _type = json['type'];
    _number = json['number'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['type'] = this._type;
    data['number'] = this._number;
    return data;
  }
}

Popularity 10/10 Helpfulness 1/10 Language javascript

Source: javiercbk.github.io

Tags: dart

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Contributed on Aug 21 2022

Mert Erkoç

0 Answers Avg Quality 2/10

json to dart

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class Autogenerated {
  int? id;
  int? age;
  String? name;

  Autogenerated({this.id, this.age, this.name});

  Autogenerated.fromJson(Map<String, dynamic> json) {
    id = json['id'];
    age = json['age'];
    name = json['name'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['id'] = this.id;
    data['age'] = this.age;
    data['name'] = this.name;
    return data;
  }
}

Popularity 10/10 Helpfulness 1/10 Language javascript

Source: javiercbk.github.io

Tags: dart

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Contributed on Aug 25 2022

anss 5286

0 Answers Avg Quality 2/10

Longest Substring Without Repeating Characters

Comment

class Solution {

    /**
     * @param String $s
     * @return Integer
     */
    function lengthOfLongestSubstring($s) {
        
    }
}

Popularity 9/10 Helpfulness 1/10 Language php

Source: Grepper

Tags: longest-substring longest-substrin

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

longest substring without repeating characters

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json to dart

Longest Substring Without Repeating Characters

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