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require('child_process'); show log

Blushing Bug answered on August 22, 2022 Popularity 1/10 Helpfulness 3/10

answer require('child_process'); show log

require('child_process'); show log

Comment

var spawn = require('child_process').spawn,
    ls    = spawn('ls', ['-lh', '/usr']);

ls.stdout.on('data', function (data) {
  console.log('stdout: ' + data.toString());
});

ls.stderr.on('data', function (data) {
  console.log('stderr: ' + data.toString());
});

ls.on('exit', function (code) {
  console.log('child process exited with code ' + code.toString());
});

Popularity 1/10 Helpfulness 3/10 Language javascript

Source: stackoverflow.com

Tags: javascript show

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