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Find first repeating element in an array of integers

Golu Rawat answered on August 24, 2022 Popularity 8/10 Helpfulness 1/10

answer Find first repeating element in an array of integers

related Find first repeating element in an array of integers

Find first repeating element in an array of integers

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/* Java program to find first repeating element in arr[] */
import java.util.*;
 
class Main
{
    // This function prints the first repeating element in arr[]
    static void printFirstRepeating(int arr[])
    {
        // Initialize index of first repeating element
        int min = -1;
 
        // Creates an empty hashset
        HashSet<Integer> set = new HashSet<>();
 
        // Traverse the input array from right to left
        for (int i=arr.length-1; i>=0; i--)
        {
            // If element is already in hash set, update min
            if (set.contains(arr[i]))
                min = i;
 
            else   // Else add element to hash set
                set.add(arr[i]);
        }
 
        // Print the result
        if (min != -1)
          System.out.println("The first repeating element is " + arr[min]);
        else
          System.out.println("There are no repeating elements");
    }
 
    // Driver method to test above method
    public static void main (String[] args) throws java.lang.Exception
    {
        int arr[] = {10, 5, 3, 4, 3, 5, 6};
        printFirstRepeating(arr);
    }
}

Popularity 8/10 Helpfulness 1/10 Language java

Source: www.geeksforgeeks.org

Tags: element find java

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Contributed on Aug 24 2022

Golu Rawat

0 Answers Avg Quality 2/10

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Find first repeating element in an array of integers

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/*package whatever //do not write package name here */
 
import java.io.*;
class GFG {
    public static int firstRepeated(int[] arr, int n)
    {
        int max = 0;
        for (int x = 0; x < n; x++) {
            if (arr[x] > max) {
                max = arr[x];
            }
        }
        int temp[]
            = new int[max + 1]; // the idea is to use
                                // temporary array as hashmap
       // Arrays.fill(temp, 0);
 
        for (int x = 0; x < n; x++) {
            int num = arr[x];
            temp[num]++;
        }
 
        for (int x = 0; x < n; x++) {
            int num = arr[x];
            if (temp[num] > 1) {
                return x;
            }
        }
 
        return -1; // if no repeating element found
    }
    public static void main(String[] args)
    {
        int[] arr = { 10, 5, 3, 4, 3, 5, 6 };
 
        int n = arr.length;
        int index = firstRepeated(
            arr,
            arr.length); // index Of 1st repeating number
        if (index != -1) {
            System.out.println("1st Repeating Number is  "
                               + arr[index]);
        }
        else {
            System.out.println("No Repeating Number Found");
        }
    }
}

Popularity 8/10 Helpfulness 2/10 Language whatever

Source: www.geeksforgeeks.org

Tags: whatever element find whate

Link to this answer
Share Copy Link

Contributed on Aug 24 2022

Golu Rawat

0 Answers Avg Quality 2/10

Find first repeating element in an array of integers

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Find first repeating element in an array of integers

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Find first repeating element in an array of integers

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