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two sum leetcode

siam88 answered on March 18, 2022 Popularity 10/10 Helpfulness 2/10

answer two sum leetcode

two sum leetcode

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#Leetcode Two Sum in Javascript

var twoSum = function(numbs, target) {



let result = "";

if (result === "") {
  for (let i = 0; i < numbs.length; i++) {
    for (let j = 0; j < numbs.length; j++) {
       

      if (i!== j) {

        if (numbs[i] + numbs[j] === target) {
            result=[j, i];

        }
      }
    }
  }
}
return result

};

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript sum

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Contributed on Aug 29 2022

siam88

0 Answers Avg Quality 2/10

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leetcode two sum solution

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-1

class Solution {
    public int[] twoSum(int[] nums, int target) {
        int arr[]= new int[2];
        for(int i =0; i<nums.length; i++){
            for(int j= i+1; j< nums.length; j++){
            if(nums[i]+ nums[j]== target){
            arr[0]= i;
            arr[1] = j;
            }
            }
        }
        
        return arr;
        
    }
}

Popularity 10/10 Helpfulness 2/10 Language java

Source: Grepper

Tags: java

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Contributed on Aug 22 2022

Manifest

0 Answers Avg Quality 2/10

leet code two sum

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#Leetcode Two Sum in Python


class Solution(object):
    def twoSum(self, arr, target):
        final = []
        for i in range(len(arr) - 1):
            for j in range(i+1,len(arr)):
                if arr[i] + arr[j] == target:
                    final.append(i)
                    final.append(j)
        return final

Popularity 10/10 Helpfulness 2/10 Language whatever

Source: leetcode.com

Tags: sum

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Contributed on Mar 18 2022

Excited Echidna

0 Answers Avg Quality 2/10

leetcode 2 sum algorithm solution

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def twoSum(nums, target):
    # Create a dictionary to store elements and their indices
    num_dict = {}
    
    # Iterate through the array
    for i, num in enumerate(nums):
        # Calculate the complement (the value needed to reach the target)
        complement = target - num
        
        # Check if the complement exists in the dictionary
        if complement in num_dict:
            # Return the indices of the current number and its complement
            return [num_dict[complement], i]
        
        # If the complement doesn't exist, add the current number and its index to the dictionary
        num_dict[num] = i
    
    # If no solution is found, return an empty list
    return []

# Example usage
nums = [2, 7, 11, 15]
target = 9
result = twoSum(nums, target)
print(result)  # Output: [0, 1] (nums[0] + nums[1] = 2 + 7 = 9)

Popularity 9/10 Helpfulness 2/10 Language python

Source: chat.openai.com

Tags: algorithm algo

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Contributed on Jul 06 2023

Kaddu Livingstone

0 Answers Avg Quality 2/10

leetcode two sum ii

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class Solution:
    def twoSum(self, numbers: List[int], target: int) -> List[int]:

        start = 0 
        end = len(numbers) -1

        while start < end:
            tempSum = numbers[start] + numbers[end]
            if tempSum == target:
                return start+1, end+1
            elif tempSum >= target:
                end -= 1
            else: 
                start +=1

Popularity 9/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: python py

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Contributed on Mar 20 2023

Hacked.fyi

0 Answers Avg Quality 2/10

leetcode 2 sum

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class Solution:
    def twoSum(self, input: List[int], target: int) -> List[int]:
        seen = []

        for indvInput in range(0, len(input)):
            remainder = target - input[indvInput]

            if remainder in seen:
                return (input.index(remainder),indvInput)
            
            seen.append(input[indvInput])

Popularity 10/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: python py

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Contributed on Mar 20 2023

Hacked.fyi

0 Answers Avg Quality 2/10

two sum leetcode

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