merge sort

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// Merges two subarrays of arr[].
// First subarray is arr[l..m]
// Second subarray is arr[m+1..r]
function merge(arr, l, m, r)
{
    var n1 = m - l + 1;
    var n2 = r - m;
  
    // Create temp arrays
    var L = new Array(n1); 
    var R = new Array(n2);
  
    // Copy data to temp arrays L[] and R[]
    for (var i = 0; i < n1; i++)
        L[i] = arr[l + i];
    for (var j = 0; j < n2; j++)
        R[j] = arr[m + 1 + j];
  
    // Merge the temp arrays back into arr[l..r]
  
    // Initial index of first subarray
    var i = 0;
    // Initial index of second subarray
    var j = 0;
    // Initial index of merged subarray
    var k = l;
  
    while (i < n1 && j < n2) {
        if (L[i] <= R[j]) {
            arr[k] = L[i];
            i++;
        }
        else {
            arr[k] = R[j];
            j++;
        }
        k++;
    }
  
    // Copy the remaining elements of
    // L[], if there are any
    while (i < n1) {
        arr[k] = L[i];
        i++;
        k++;
    }
  
    // Copy the remaining elements of
    // R[], if there are any
    while (j < n2) {
        arr[k] = R[j];
        j++;
        k++;
    }
}
  
// l for left index r is
// right index of the sub-array
// of arr to be sorted
function mergeSort(arr,l, r){
    if(l>=r){
        return;//returns recursively
    }
    var m =l+ parseInt((r-l)/2);
    mergeSort(arr,l,m);
    mergeSort(arr,m+1,r);
    merge(arr,l,m,r);
}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: sorting-algorithms.me

Tags: javascript merge

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Contributed on Sep 13 2022

katanton reckless

0 Answers Avg Quality 2/10

merge sort

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26

//merge sort
#include <iostream>

using namespace std;
void merge(int arr[],int start,int mid,int end)
{
    int n1=mid-start+1;
    int n2=end-mid;
    int l[n1],m[n2];
    for(int i=0;i<n1;i++)
    {
        l[i]=arr[start+i];
    }
    for(int j=0;j<n2;j++)
    {
        m[j]=arr[mid+1+j];
    }
    int i=0;
    int j=0;
    int k=start;
    while(i<n1&&j<n2)
    {
        if(l[i]<m[j])
        {
            arr[k]=l[i];
            k++;
            i++;
        }
        else
        {
            arr[k]=m[j];
            k++;
            j++;
        }
    }
    while(i<n1)
    {
        arr[k]=l[i];
        k++;
        i++;
    }
    while(j<n2)
    {
        arr[k]=m[j];
        k++;
        j++;
    }
}
void mergesort(int arr[],int start,int end)
{
    if(start<end)
    {
        int mid=(start+end)/2;
        mergesort(arr,start,mid);
        mergesort(arr,mid+1,end);
        merge(arr,start,mid,end);
    }
}
void display(int arr[],int n)
{
    for(int i=0;i<n;i++)
    {
        cout<<arr[i]<<" ";
    }
    cout<<endl;
}

int main()
{
    int n;
    cout<<"enter the size of the array:"<<endl;
    cin>>n;
    cout<<"enter the elements of the array:"<<endl;
    int arr[n];
    for(int i=0;i<n;i++)
    {
        cin>>arr[i];
    }
    cout<<"array as it is:"<<endl;
    display(arr,n);
    cout<<"sorted array:"<<endl;
    mergesort(arr,0,n-1);
    display(arr,n);
    return 0;
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on May 27 2021

ujjwal sotra

0 Answers Avg Quality 2/10

merge sort

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1

// C#

using System;

class MergeSortAlgorithm
{
    public static void MergeSort(int[] arr)
    {
        if (arr == null || arr.Length <= 1)
            return;

        int[] temp = new int[arr.Length];
        MergeSortHelper(arr, 0, arr.Length - 1, temp);
    }

    private static void MergeSortHelper(int[] arr, int left, int right, int[] temp)
    {
        if (left < right)
        {
            int mid = left + (right - left) / 2;
            MergeSortHelper(arr, left, mid, temp);
            MergeSortHelper(arr, mid + 1, right, temp);
            Merge(arr, left, mid, right, temp);
        }
    }

    private static void Merge(int[] arr, int left, int mid, int right, int[] temp)
    {
        Array.Copy(arr, left, temp, left, right - left + 1);

        int i = left;
        int j = mid + 1;
        int k = left;

        while (i <= mid && j <= right)
        {
            if (temp[i] <= temp[j])
            {
                arr[k] = temp[i];
                i++;
            }
            else
            {
                arr[k] = temp[j];
                j++;
            }
            k++;
        }

        while (i <= mid)
        {
            arr[k] = temp[i];
            k++;
            i++;
        }
    }

    static void Main(string[] args)
    {
        int[] arr = { 12, 11, 13, 5, 6, 7 };

        Console.WriteLine("Given array is ");
        PrintArray(arr);

        MergeSort(arr);

        Console.WriteLine("\nSorted array is ");
        PrintArray(arr);
    }

    static void PrintArray(int[] arr)
    {
        foreach (var item in arr)
        {
            Console.Write(item + " ");
        }
        Console.WriteLine();
    }
}

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: algorithm algo

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Contributed on Mar 20 2024

mrasadatik

0 Answers Avg Quality 2/10

This pseudocode describes the Merge Sort algorithm, which recursively divides the input array into smaller sub-arrays until each sub-array has only one element. Then, it merges these sub-arrays back together in sorted order. This algorithm maintains a time complexity of O(n log n) and uses additional space for the temporary arrays during merging, also O(n).

mergeSort(arr):
    if length of arr <= 1:
        return arr
    
    mid = length of arr / 2
    left = mergeSort(arr[0:mid])
    right = mergeSort(arr[mid:end])
    
    return merge(left, right)

merge(left, right):
    result = []
    while left is not empty and right is not empty:
        if first element of left <= first element of right:
            append first element of left to result
            remove first element from left
        else:
            append first element of right to result
            remove first element from right
    
    append remaining elements of left to result
    append remaining elements of right to result
    
    return result

Popularity 10/10 Helpfulness 2/10 Language whatever

Source: Grepper

Tags: merge merg

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Contributed on Mar 20 2024

mrasadatik

0 Answers Avg Quality 2/10

merge sort

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function mergeSort(arr) {
    if (arr.length <= 1) {
        return arr;
    }

    const mid = Math.floor(arr.length / 2);
    const left = mergeSort(arr.slice(0, mid));
    const right = mergeSort(arr.slice(mid));

    return merge(left, right);
}

function merge(left, right) {
    let result = [];
    let leftIndex = 0;
    let rightIndex = 0;

    while (leftIndex < left.length && rightIndex < right.length) {
        if (left[leftIndex] < right[rightIndex]) {
            result.push(left[leftIndex]);
            leftIndex++;
        } else {
            result.push(right[rightIndex]);
            rightIndex++;
        }
    }

    return result.concat(left.slice(leftIndex)).concat(right.slice(rightIndex));
}

// Example usage:
const arr = [12, 11, 13, 5, 6, 7];
console.log("Given array is");
console.log(arr);

const sortedArr = mergeSort(arr);
console.log("\nSorted array is");
console.log(sortedArr);

Popularity 8/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: algorithm javascript

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Contributed on Mar 20 2024

mrasadatik

0 Answers Avg Quality 2/10

merge sort

Comment

2

this website explains merge sort well. It also has other sorts as well.
https://computerneek.org/sortingal.html

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Source: Grepper

Tags: merge merg

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Contributed on Nov 26 2022

Frantic Fox

0 Answers Avg Quality 2/10

merge sort

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#include <iostream>
#include <vector>

void merge(std::vector<int>& arr, int left, int mid, int right) {
    int n1 = mid - left + 1;
    int n2 = right - mid;

    std::vector<int> L(n1), R(n2);

    for (int i = 0; i < n1; i++)
        L[i] = arr[left + i];
    for (int j = 0; j < n2; j++)
        R[j] = arr[mid + 1 + j];

    int i = 0, j = 0, k = left;
    while (i < n1 && j < n2) {
        if (L[i] <= R[j]) {
            arr[k] = L[i];
            i++;
        } else {
            arr[k] = R[j];
            j++;
        }
        k++;
    }

    while (i < n1) {
        arr[k] = L[i];
        i++;
        k++;
    }

    while (j < n2) {
        arr[k] = R[j];
        j++;
        k++;
    }
}

void mergeSort(std::vector<int>& arr, int left, int right) {
    if (left < right) {
        int mid = left + (right - left) / 2;

        mergeSort(arr, left, mid);
        mergeSort(arr, mid + 1, right);

        merge(arr, left, mid, right);
    }
}

int main() {
    std::vector<int> arr = {12, 11, 13, 5, 6, 7};
    int arr_size = arr.size();

    std::cout << "Given array is \n";
    for (int i = 0; i < arr_size; i++)
        std::cout << arr[i] << " ";
    std::cout << std::endl;

    mergeSort(arr, 0, arr_size - 1);

    std::cout << "\nSorted array is \n";
    for (int i = 0; i < arr_size; i++)
        std::cout << arr[i] << " ";
    std::cout << std::endl;

    return 0;
}

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: algorithm algo

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Contributed on Mar 20 2024

mrasadatik

0 Answers Avg Quality 2/10

merge sort

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1

<?php    
  
/* Function to merge the subarrays of a[] */  
function merge(&$a, $beg, $mid, $end)    
{    
    $n1 = ($mid - $beg) + 1;    
    $n2 = $end - $mid;    
      
   /* temporary Arrays */  
        $LeftArray = array($n1);  
        $RightArray = array($n2);  
      
    /* copy data to temp arrays */  
    for ($i = 0; $i < $n1; $i++)    
    $LeftArray[$i] = $a[$beg + $i];    
    for ($j = 0; $j < $n2; $j++)    
    $RightArray[$j] = $a[$mid + 1 + $j];    
      
    $i = 0; /* initial index of first sub-array */  
    $j = 0; /* initial index of second sub-array */   
    $k = $beg;  /* initial index of merged sub-array */  
      
    while ($i<$n1 && $j<$n2)    
    {    
        if($LeftArray[$i] <= $RightArray[$j])    
        {    
            $a[$k] = $LeftArray[$i];    
            $i++;    
        }    
        else    
        {    
            $a[$k] = $RightArray[$j];    
            $j++;    
        }    
        $k++;    
    }    
    while ($i<$n1)    
    {    
        $a[$k] = $LeftArray[$i];    
        $i++;    
        $k++;    
    }    
      
    while ($j<$n2)    
    {    
        $a[$k] = $RightArray[$j];    
        $j++;    
        $k++;    
    }    
}    
  
function mergeSort(&$a, $beg, $end)  
{  
    if ($beg < $end)   
    {  
        $mid = (int)(($beg + $end) / 2);  
        mergeSort($a, $beg, $mid);  
        mergeSort($a, $mid + 1, $end);  
        merge($a, $beg, $mid, $end);  
    }  
}  
  
/* Function to print array elements */  
    function printArray($a, $n)  
    {  
    for($i = 0; $i < $n; $i++)    
    {    
        print_r($a[$i]);    
        echo " ";    
    }        
    }  
  
    $a = array( 10, 29, 23, 6, 30, 15, 38, 40 );    
    $n = count($a);  
    echo "Before sorting array elements are - <br>";    
    printArray($a, $n);  
    mergeSort($a, 0, $n - 1);  
    echo "<br> After sorting array elements are - <br>";    
    printArray($a, $n);  
?>

Popularity 10/10 Helpfulness 2/10 Language php

Source: Grepper

Tags: merge merg

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Contributed on Mar 16 2023

Shadow

0 Answers Avg Quality 2/10

merge sort

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0

#include <stdio.h>
#include <stdlib.h>

void merge(int arr[], int left, int mid, int right) {
    int i, j, k;
    int n1 = mid - left + 1;
    int n2 = right - mid;

    // Create temporary arrays
    int* L = (int*)malloc(n1 * sizeof(int));
    int* R = (int*)malloc(n2 * sizeof(int));

    // Copy data to temporary arrays L[] and R[]
    for (i = 0; i < n1; i++)
        L[i] = arr[left + i];
    for (j = 0; j < n2; j++)
        R[j] = arr[mid + 1 + j];

    // Merge the temporary arrays back into arr[left..right]
    i = 0; // Initial index of first subarray
    j = 0; // Initial index of second subarray
    k = left; // Initial index of merged subarray
    while (i < n1 && j < n2) {
        if (L[i] <= R[j]) {
            arr[k] = L[i];
            i++;
        }
        else {
            arr[k] = R[j];
            j++;
        }
        k++;
    }

    // Copy the remaining elements of L[], if there are any
    while (i < n1) {
        arr[k] = L[i];
        i++;
        k++;
    }

    // Copy the remaining elements of R[], if there are any
    while (j < n2) {
        arr[k] = R[j];
        j++;
        k++;
    }

    // Free temporary arrays
    free(L);
    free(R);
}

void mergeSort(int arr[], int left, int right) {
    if (left < right) {
        int mid = left + (right - left) / 2;

        // Sort first and second halves
        mergeSort(arr, left, mid);
        mergeSort(arr, mid + 1, right);

        // Merge the sorted halves
        merge(arr, left, mid, right);
    }
}

int main() {
    int arr[] = { 12, 11, 13, 5, 6, 7 };
    int arr_size = sizeof(arr) / sizeof(arr[0]);

    printf("Given array is \n");
    for (int i = 0; i < arr_size; i++)
        printf("%d ", arr[i]);
    printf("\n");

    mergeSort(arr, 0, arr_size - 1);

    printf("\nSorted array is \n");
    for (int i = 0; i < arr_size; i++)
        printf("%d ", arr[i]);
    printf("\n");

    return 0;
}

Popularity 8/10 Helpfulness 2/10 Language c

Source: Grepper

Tags: algorithm algo

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Contributed on Mar 20 2024

mrasadatik

0 Answers Avg Quality 2/10

merge sort

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def mergeSort(arr):
    if len(arr) > 1:
  
         # Finding the mid of the array
        mid = len(arr)//2
  
        # Dividing the array elements
        L = arr[:mid]
  
        # into 2 halves
        R = arr[mid:]
  
        # Sorting the first half
        mergeSort(L)
  
        # Sorting the second half
        mergeSort(R)
  
        i = j = k = 0
  
        # Copy data to temp arrays L[] and R[]
        while i < len(L) and j < len(R):
            if L[i] < R[j]:
                arr[k] = L[i]
                i += 1
            else:
                arr[k] = R[j]
                j += 1
            k += 1
  
        # Checking if any element was left
        while i < len(L):
            arr[k] = L[i]
            i += 1
            k += 1
  
        while j < len(R):
            arr[k] = R[j]
            j += 1
            k += 1

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Tags: merge merg

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Contributed on Feb 17 2022

Defiant Donkey

0 Answers Avg Quality 2/10

merge sort

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