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the fibonacci sequence

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Red Team answered on December 16, 2020 Popularity 10/10 Helpfulness 2/10

answer the fibonacci sequence

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the fibonacci sequence

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int fabseq(int nth){
        if (nth == 1 || nth == 2){
            return 1;
        }
        int equ = (1/sqrt(5))*pow(((1+sqrt(5))/2), nth)-(1/sqrt(5))*pow((1-sqrt(5))/2, nth);
        return equ;
}

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Contributed on Oct 04 2022

Red Team

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fibonacci sequence

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0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ...

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Source: www.mathsisfun.com

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Contributed on Dec 16 2020

Marton

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fibonacci sequence

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function _fib(number) {
    if (number === 0 || number === 1) {
        return number;
    } else {
        return _fib(number - 1) + _fib(number - 2)
    }
}

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Contributed on Dec 27 2021

Hassan Hamdan

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Fibonacci Sequence

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// 定義一個計算 Fibonacci Sequence 的函式
function fibonacci(n) {
  if (n <= 1) {
    return n; // 基本情況: 當 n 為 0 或 1 時，返回 n
  } else {
    // 否則，遞迴計算前兩個數字的和
    return fibonacci(n - 1) + fibonacci(n - 2);
  }
}

// 創建一個函式來展示 Fibonacci Sequence
function displayFibonacciSequence(n) {
  for (let i = 0; i < n; i++) {
    console.log(fibonacci(i));
  }
}

// 使用示例：顯示前 10 個 Fibonacci 數字
displayFibonacciSequence(10);

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Contributed on Oct 31 2023

Unsightly Unicorn

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fibonacci sequence code

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Language: Rust (not supported by grepper)

fn fibcalculate(x:i32) -> i32 {
    let mut two_nums_ago = 0;
    let mut current_num = 1;
    let mut last_num = 0;
    for i in 1..x {                   // or 0..x if you start fibonacci from 0, although that breaks the math law as 0+0 != 1
        last_num = current_num;
        current_num += two_nums_ago;
        two_nums_ago = last_num;
    }
    return current_num;
}

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Contributed on Dec 22 2022

Wrong Walrus

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Fibonacci sequence

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function myFib(n) {
    if (isNaN(n) || Math.floor(n) !== n)
        return "Not an integer value!";
    if (n === 0 || n === 1)
        return 3;
    else
        return myFib(n - 1) + myFib(n - 2);
}

console.log(myFib(5));

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Contributed on Aug 17 2021

Talented Tarsier

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Fibonacci Sequence

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nterms = int(input())

x, y, z = 1, 1, 0

if nterms == 1:
   print(x)
else:
   while z < nterms:
       print(x, end=" ")
       nth = x + y
       x = y
       y = nth
       z += 1

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Contributed on Oct 25 2022

baguette

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the fibonacci sequence

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