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uri 1021 solution in c

MD. Yeasine Dewan Shawon answered on October 14, 2022 Popularity 4/10 Helpfulness 3/10

answer uri 1021 solution in c

uri 1021 solution in c

Comment

#include <stdio.h>
 
int main()
 
{
 
    double n, d[] = {100.0, 50.0, 20.0, 10.0, 5.0, 2.0, 1.0, 0.5, 0.25, 0.10, 0.05, 0.01};
 
    int t = 0, c;
 
    scanf("%lf", &n);
 
    printf("NOTAS:\n");
 
    t = 0;
 
    n+=1e-9;
 
    while (d[t] >= 0.01)
 
    {
 
        c = 0;
 
        while (n >= d[t])
 
        {
 
            n -= d[t];
 
            c++;
 
        }
 
        if (d[t] == 1.0)
 
            printf("MOEDAS:\n");
 
        if (d[t] >= 2.0 )
 
            printf("%d nota(s) de R$ %.2f\n", c, d[t]);
 
        else
 
            printf("%d moeda(s) de R$ %.2f\n", c, d[t]);
 
        t++;
 
    }
 
    return 0;
 
}

Popularity 4/10 Helpfulness 3/10 Language c

Source: www.codeshikhi.com

Tags: c solution uri

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Contributed on Oct 14 2022

MD. Yeasine Dewan Shawon

0 Answers Avg Quality 2/10

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1021 uri solution

Comment

#include <iostream>

using namespace std;

int main(){
    double N;
    int inteiro, aux, aux1;

    while(cin >> N){

    inteiro = N;
    N = 100*N;
    aux1 = N;


    cout << "NOTAS:\n";
    cout << inteiro/100 << " nota(s) de R$ 100.00\n";
    aux = (inteiro%100);
    cout << aux/50 << " nota(s) de R$ 50.00\n";
    aux = (aux%50);
    cout << aux/20 << " nota(s) de R$ 20.00\n";
    aux = (aux%20);
    cout << aux/10 << " nota(s) de R$ 10.00\n";
    aux = (aux%10);
    cout << aux/5 << " nota(s) de R$ 5.00\n";
    aux = (aux%5);
    cout << aux/2 << " nota(s) de R$ 2.00\n";
    aux = (aux%2);
    cout << "MOEDAS:\n";
    cout << aux/1 << " moeda(s) de R$ 1.00\n";

    aux1 = aux1%100;
    cout <<  aux1/50 << " moeda(s) de R$ 0.50\n";
    aux1 = aux1%50;
    cout <<  aux1/25 << " moeda(s) de R$ 0.25\n";
    aux1 = aux1%25;
    cout <<  aux1/10 << " moeda(s) de R$ 0.10\n";
    aux1 = aux1%10;
    cout <<  aux1/5 << " moeda(s) de R$ 0.05\n";
    aux1 = aux1%5;
    cout <<  aux1/1 << " moeda(s) de R$ 0.01\n";
    }

    return 0;
}

Popularity 3/10 Helpfulness 2/10 Language cpp

Source: www.codeshikhi.com

Tags: c++ uri solution

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Contributed on Oct 30 2022

MD. MOORSAHA - UL- ISLAM NOOR 203-35-3138

0 Answers Avg Quality 2/10

uri 1036 solution in c

Comment

#include<stdio.h>

#include<math.h>

int main()

{

    double a,b,c,r1,r2,del;

    scanf("%lf %lf %lf",&a,&b,&c);

    del=(b*b)-(4*a*c);

    r1=(-b+sqrt(del))/(2*a);

    r2=(-b-sqrt(del))/(2*a);

    if(a!=0 && del>0)

    {

        printf("R1 = %.5lf\nR2 = %.5lf\n",r1,r2);

    }

    else printf("Impossivel calcular\n");

 

 

    return 0;

}

Popularity 6/10 Helpfulness 2/10 Language c

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Tags: solution c uri

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Contributed on Oct 16 2022

MD. Yeasine Dewan Shawon

0 Answers Avg Quality 2/10

uri problem 1015 solution in c

Comment

#include <stdio.h>
    #include <math.h>
    
    int main()
    {
     double x1, x2, y1, y2, dist;
    
     scanf("%lf %lf %lf %lf", &x1, &y1, &x2, &y2);
    
     dist = sqrt(pow(x2-x1,2)+pow(y2-y1,2));
    
     printf("%.4lf\n", dist);
     return 0;
    }

Popularity 3/10 Helpfulness 1/10 Language c

Source: www.beecrowd.com.br

Tags: uri c solution

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Contributed on Oct 14 2022

MD. Yeasine Dewan Shawon

0 Answers Avg Quality 2/10

uri 1021 solution in c

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