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Combination sum

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Sumit Rawal answered on August 17, 2022 Popularity 7/10 Helpfulness 1/10

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Combination sum

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//User function template for JAVA
class Pair{
    int first;
    int second;
    public Pair(int i,int j){
        first=i;
        second=j;
    }
    @Override
    public boolean equals(Object o){
        if(this==o)return true;
        if(o==null)return false;
        if(this.getClass()!=o.getClass())return false;
        Pair oo=(Pair)o;
        return oo.first==this.first&&oo.second==this.second;
    }
    @Override
    public int hashCode(){
       // return first.hashCode()+second.hashCode();
       final int prime=31;
       int result=1;
       result=result*prime+first;
       result=result*prime+second;
       return result;
    }
    @Override
    public String toString(){
        return "("+first+","+second+")";
    }
}
class Solution
{
    //Function to return a list of indexes denoting the required 
    //combinations whose sum is equal to given number.
    static ArrayList<ArrayList<Integer>> combinationSum(ArrayList<Integer> A, int B){
        //REMOVE DUPLICATES BECAUSE IT NOT AFFECT FINAL RESULT BASED ON THAT The same number may be chosen from the array any number of times 
        TreeSet<Integer> tr=new TreeSet<Integer>(A);
        A.clear();
        for(Integer i:tr){
           A.add(i);
        }
        //sort
        Collections.sort(A);
        
        
        Pair[][] hm=new Pair[B+1][A.size()+1];//[i][j]:how many combinations to form sum i by head j elements of A
        
        //if use TreeMap<Pair, ArrayList<ArrayList<Integer>>>, then class Pair have to implement Comparable interface
        HashMap<Pair, ArrayList<ArrayList<Integer>>> m=new HashMap<Pair, ArrayList<ArrayList<Integer>>>();
        
        for(int i=0;i<=B;i++){
            for(int j=0;j<=A.size();j++){
                hm[i][j]=new Pair(i,j);
            }
        }
        //System.out.println(howMany[0][1].second);System.out.println(howMany[2][0].second);
        
        //ArrayList<ArrayList<Integer>> z=new ArrayList<ArrayList<Integer>>();
        for(int i=1;i<=B;i++){
            for(int j=1;j<=A.size();j++){
                ArrayList<ArrayList<Integer>> z=new ArrayList<ArrayList<Integer>>();
                ArrayList<ArrayList<Integer>> y=m.get(hm[i][j-1]);//exclude jth element
                if(y!=null){
                    z=new ArrayList<ArrayList<Integer>>(y);
                }
                int t=A.get(j-1);
                if(i>t){
                    y=m.get(hm[i-t][A.size()]);//include jth element
                    if(y!=null){
                        for(ArrayList<Integer> a:y){//because arraylist implements iterable interface
                            if(a.get(a.size()-1)<=t){// Elements in a combination ascending
                                ArrayList<Integer> b=new ArrayList<Integer>(a);
                                b.add(t);
                                z.add(b);
                            }
                        }
                    }
                }
                if(i==t){
                   ArrayList<Integer> c=new ArrayList<Integer>();
                   c.add(t);
                   z.add(c);
                }
                if(z.size()!=0){
                    m.put(hm[i][j],z);
                }
                
            }
        }
        ArrayList<ArrayList<Integer>> x=m.get(hm[B][A.size()]);//new ArrayList<ArrayList<Integer>>();
        if(x!=null){
            Collections.sort(x,new Comparator<ArrayList<Integer>>(){
                /*
                @Override
                public int compare(ArrayList<Integer> l1,ArrayList<Integer> l2){//because l1 and l2 already sorted
                    return l1.get(0)-l2.get(0);
                    //or -->  return l1.get(0).compareTo(l2.get(0));<--compareTo in interface Comparable<Integer> implemented by Integer
                }*/
                @Override
                public int compare(ArrayList<Integer> l1,ArrayList<Integer> l2){
                    int min=Math.min(l1.size(),l2.size());
                    for(int i=0;i<min;i++){
                        Integer i1=l1.get(i);
                        Integer i2=l2.get(i);
                        if(i1!=i2){
                            return i1.compareTo(i2); //compareTo in interface Comparable<Integer> implemented by Integer
                        }
                    }
                    return l1.size()<=l2.size()?-1:1;//Integer.valueOf(l1.size()).compareTo(Integer.valueOf(l2.size()));
                }
            });
        }else{
            x=new ArrayList<ArrayList<Integer>>();
        }
        return x;
    }
}

Popularity 7/10 Helpfulness 1/10 Language whatever

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Tags: sum whatever

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Contributed on Oct 18 2022

Sumit Rawal

0 Answers Avg Quality 2/10

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class Solution {
    public List<List<Integer>> combinationSum(int[] candidates, int target) {
        
    }
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Popularity 10/10 Helpfulness 1/10 Language java

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Contributed on Aug 17 2022

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Combination Sum

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/**
 * Return an array of arrays of size *returnSize.
 * The sizes of the arrays are returned as *returnColumnSizes array.
 * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().
 */
int** combinationSum(int* candidates, int candidatesSize, int target, int* returnSize, int** returnColumnSizes){

}

Popularity 8/10 Helpfulness 1/10 Language c

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Contributed on Aug 17 2022

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Combination Sum

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public class Solution {
    public IList<IList<int>> CombinationSum(int[] candidates, int target) {
        
    }
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Popularity 8/10 Helpfulness 1/10 Language csharp

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Tags: c# sum

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Contributed on Aug 17 2022

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/**
 * @param {number[]} candidates
 * @param {number} target
 * @return {number[][]}
 */
var combinationSum = function(candidates, target) {
    
};

Popularity 7/10 Helpfulness 1/10 Language javascript

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Contributed on Aug 17 2022

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Combination Sum

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# @param {Integer[]} candidates
# @param {Integer} target
# @return {Integer[][]}
def combination_sum(candidates, target)
    
end

Popularity 7/10 Helpfulness 1/10 Language ruby

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Tags: ruby sum

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Contributed on Aug 17 2022

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Combination Sum

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class Solution {
    func combinationSum(_ candidates: [Int], _ target: Int) -> [[Int]] {
        
    }
}

Popularity 7/10 Helpfulness 1/10 Language swift

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Contributed on Aug 17 2022

CodeBlack reactor

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Combination Sum

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class Solution {

    /**
     * @param Integer[] $candidates
     * @param Integer $target
     * @return Integer[][]
     */
    function combinationSum($candidates, $target) {
        
    }
}

Popularity 7/10 Helpfulness 1/10 Language php

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Tags: php sum

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Contributed on Aug 17 2022

CodeBlack reactor

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Combination Sum

Comment

function combinationSum(candidates: number[], target: number): number[][] {

};

Popularity 8/10 Helpfulness 1/10 Language typescript

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Contributed on Aug 17 2022

CodeBlack reactor

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Combination Sum II

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class Solution {
public:
    vector<vector<int>> combinationSum2(vector<int>& candidates, int target) {
        
    }
};

Popularity 8/10 Helpfulness 1/10 Language cpp

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Tags: c++ sum

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Combination Sum II

Comment


/**
 * Return an array of arrays of size *returnSize.
 * The sizes of the arrays are returned as *returnColumnSizes array.
 * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().
 */
int** combinationSum2(int* candidates, int candidatesSize, int target, int* returnSize, int** returnColumnSizes){

}

Popularity 7/10 Helpfulness 1/10 Language c

Source: Grepper

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Combination sum

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