Breaking News: Grepper is joining You.com. Read the official announcement!

longest common subsequence

Add Answer

Sumit Rawal answered on October 19, 2022 Popularity 10/10 Helpfulness 1/10

answer longest common subsequence

related longest common subsequence (str, str)

related print longest common subsequence

longest common subsequence

Comment

class Solution
{
    
    //Function to find the length of longest common subsequence in two strings.
    static int lcs(int x, int y, String s1, String s2)
    {
         int dp[][] = new int[x+1][y+1];
         for(int i=0;i<=x;i++)
         {
             for (int j=0;j<=y;j++)
             {
                 dp[i][j]=-1;
             }
         } 
        return lcshelper(x,y,s1,s2, dp);
    }
    
   static int lcshelper(int m,int n,String x, String y, int[][] dp)
    {
        
        if(m==0 || n==0)
            return 0;
        
        if (dp[m][n]!= -1)
            return dp[m][n];
            
        if (x.charAt(m-1)==y.charAt(n-1))
            dp[m][n] = 1+lcshelper(m-1,n-1,x,y, dp);
        else
        dp[m][n]= Math.max(lcshelper(m-1,n,x,y,dp), lcshelper(m,n-1,x,y,dp));
        return dp[m][n];
    }
    
}

Popularity 10/10 Helpfulness 1/10 Language whatever

Source: Grepper

Tags: subsequence whatever

Link to this answer
Share Copy Link

Contributed on Oct 19 2022

Sumit Rawal

0 Answers Avg Quality 2/10

Closely Related Answers

longest common subsequence (str, str)

Comment

int LongestRepeatingSubsequence(string str){
  // Code here
  int n=str.length();

  vector<int> prev(n+1,0), cur(n+1,0);

  for(int i=1;i<=n;i++){
    for(int j=1;j<=n;j++){
      if(str[i-1]==str[j-1])cur[j]=1+prev[j-1];
      else cur[j]=max(cur[j-1], prev[j]);
    }
    prev=cur;
  }
  return cur[n];
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

Link to this answer
Share Copy Link

Contributed on Jul 18 2023

Mridu Pawan

0 Answers Avg Quality 2/10

print longest common subsequence

Comment

#include <bits/stdc++.h>

using namespace std;

void lcs(string s1, string s2) {

  int n = s1.size();
  int m = s2.size();

  vector < vector < int >> dp(n + 1, vector < int > (m + 1, 0));
  for (int i = 0; i <= n; i++) {
    dp[i][0] = 0;
  }
  for (int i = 0; i <= m; i++) {
    dp[0][i] = 0;
  }

  for (int ind1 = 1; ind1 <= n; ind1++) {
    for (int ind2 = 1; ind2 <= m; ind2++) {
      if (s1[ind1 - 1] == s2[ind2 - 1])
        dp[ind1][ind2] = 1 + dp[ind1 - 1][ind2 - 1];
      else
        dp[ind1][ind2] = 0 + max(dp[ind1 - 1][ind2], dp[ind1][ind2 - 1]);
    }
  }

  int len = dp[n][m];
  int i = n;
  int j = m;

  int index = len - 1;
  string str = "";
  for (int k = 1; k <= len; k++) {
    str += "$"; // dummy string
  }

  while (i > 0 && j > 0) {
    if (s1[i - 1] == s2[j - 1]) {
      str[index] = s1[i - 1];
      index--;
      i--;
      j--;
    } else if (s1[i - 1] > s2[j - 1]) {
      i--;
    } else j--;
  }
  cout << str;
}

int main() {

  string s1 = "abcde";
  string s2 = "bdgek";

  cout << "The Longest Common Subsequence is ";
  lcs(s1, s2);
}

Popularity 8/10 Helpfulness 2/10 Language cpp

Source: takeuforward.org

Tags: c++ subsequence

Link to this answer
Share Copy Link

Contributed on Mar 27 2024

Pranay Dubey

0 Answers Avg Quality 2/10

longest common subsequence

Contents

More Related Answers

longest common subsequence

Closely Related Answers

longest common subsequence (str, str)

print longest common subsequence

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.