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do a request in golang

Fair Flatworm answered on April 9, 2022 Popularity 10/10 Helpfulness 5/10

answer do a request in golang

related golang api request

do a request in golang

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resp, err := http.Get("https://jsonplaceholder.typicode.com/posts/1")
if err != nil {
   log.Fatalln(err)
}

Popularity 10/10 Helpfulness 5/10 Language go

Source: blog.logrocket.com

Tags: go request

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Contributed on Oct 26 2022

Fair Flatworm

0 Answers Avg Quality 2/10

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golang api request

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package main

import (
	"encoding/json"
	"io/ioutil"
	"log"
	"net/http"
)

type Login struct {
	Username string `json:"username"`
	Password string `json:"password"`
}

type APIResponse struct {
	Stat_Code uint32 `json:"stat_code"`
	Stat_Msg  string `json:"stat_msg"`
}

func ApiResponse(rw http.ResponseWriter, v *APIResponse) {
	result, err := json.Marshal(v)
	if err != nil {
		log.Fatal(err)
	}
	rw.Write(result)
}

func main() {
	server := http.Server{
		Addr: ":3000",
	}

	http.HandleFunc("/", func(rw http.ResponseWriter, r *http.Request) {
		rw.Header().Set("Content-Type", "application/json")

		payload := Login{}

		body, err := ioutil.ReadAll(r.Body)
		if err != nil {
			log.Fatal(err)
		}

		err = json.Unmarshal(body, &payload)
		if err != nil {
			log.Fatal(err)
		}

		if payload.Username != "johndoe13" || payload.Password != "qwerty12" {
			ApiResponse(rw, &APIResponse{Stat_Code: http.StatusBadRequest, Stat_Msg: "Username or password mismatch"})
			defer log.Print("http request error")
			return
		}

		ApiResponse(rw, &APIResponse{Stat_Code: http.StatusOK, Stat_Msg: "Login success"})
		defer log.Print("http request success")
	})

	server.ListenAndServe()
}

Popularity 10/10 Helpfulness 4/10 Language go

Source: Grepper

Tags: api

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Contributed on Apr 09 2022

Restu Wahyu Saputra

0 Answers Avg Quality 2/10

do a request in golang

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do a request in golang

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golang api request

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