Breaking News: Grepper is joining You.com. Read the official announcement!

insertion sort java

Add Answer

An7wan answered on June 27, 2022 Popularity 10/10 Helpfulness 6/10

answer insertion sort java

related insertion sort java

related Insertion sort in Java

related Java Insertion Sort

insertion sort java

Comment

//  Insertion Sort

class InsertionSort {
    /*Function to sort array using insertion sort*/
    void insertionsort(int arr[])
    {
        int n = arr.length;
        for (int i = 1; i < n; ++i) {
            int key = arr[i];
            int r = i - 1;
  
            /* Move elements of arr[0..i-1], that are
               greater than key, to one position ahead
               of their current position */
            while (r >= 0 && arr[r] > key) {
                arr[r + 1] = arr[r];
                r = r - 1;
            }
            arr[r + 1] = key;
        }
    }
    /* A utility function to print array of size n*/
    static void printArray(int arr[])
    {
        int n = arr.length;
        for (int i = 0; i < n; ++i)
            System.out.print(arr[i] + " ");
  
        System.out.println();
    }
  
  
    // Driver method
    public static void main(String args[])
    {
        int arr[] = { 12, 11, 13, 5, 6 , 7, 90, 60, 50, 30, 54, 2, 1, 6 };
        //creates new instance of insertin sort and runs it with a given arry
        InsertionSort ob = new InsertionSort();
        ob.insertionsort(arr);
        //prints the sorted array
        printArray(arr);
    }
}

Popularity 10/10 Helpfulness 6/10 Language java

Source: Grepper

Tags: insertion-sort java

Link to this answer
Share Copy Link

Contributed on Oct 26 2022

An7wan

0 Answers Avg Quality 2/10

Closely Related Answers

insertion sort java

Comment

// Java program for implementation of Insertion Sort
class InsertionSort {
    /*Function to sort array using insertion sort*/
    void sort(int arr[])
    {
        int n = arr.length;
        for (int i = 1; i < n; ++i) {
            int key = arr[i];
            int j = i - 1;
  
            /* Move elements of arr[0..i-1], that are
               greater than key, to one position ahead
               of their current position */
            while (j >= 0 && arr[j] > key) {
                arr[j + 1] = arr[j];
                j = j - 1;
            }
            arr[j + 1] = key;
        }
    }
  
    /* A utility function to print array of size n*/
    static void printArray(int arr[])
    {
        int n = arr.length;
        for (int i = 0; i < n; ++i)
            System.out.print(arr[i] + " ");
  
        System.out.println();
    }
  
    // Driver method
    public static void main(String args[])
    {
        int arr[] = { 12, 11, 13, 5, 6 };
  
        InsertionSort ob = new InsertionSort();
        ob.sort(arr);
  
        printArray(arr);
    }
} /* This code is contributed by Rajat Mishra. */

Popularity 9/10 Helpfulness 5/10 Language java

Source: www.geeksforgeeks.org

Tags: insertion-sort inse

Link to this answer
Share Copy Link

Contributed on Oct 12 2022

An7wan

0 Answers Avg Quality 2/10

Insertion sort in Java

Comment

// Insertion sort in Java

import java.util.Arrays;

class InsertionSort {

  void insertionSort(int array[]) {
    int size = array.length;

    for (int step = 1; step < size; step++) {
      int key = array[step];
      int j = step - 1;

      // Compare key with each element on the left of it until an element smaller than
      // it is found.
      // For descending order, change key<array[j] to key>array[j].
      while (j >= 0 && key < array[j]) {
        array[j + 1] = array[j];
        --j;
      }

      // Place key at after the element just smaller than it.
      array[j + 1] = key;
    }
  }

  // Driver code
  public static void main(String args[]) {
    int[] data = { 9, 5, 1, 4, 3 };
    InsertionSort is = new InsertionSort();
    is.insertionSort(data);
    System.out.println("Sorted Array in Ascending Order: ");
    System.out.println(Arrays.toString(data));
  }
}

Popularity 9/10 Helpfulness 3/10 Language java

Source: www.programiz.com

Tags: insertion-sort inse

Link to this answer
Share Copy Link

Contributed on Jun 27 2022

Energetic Emu

0 Answers Avg Quality 2/10

Java Insertion Sort

Comment

// Java Insertion Sort
// -------------------

/* 
   Time Complexity
     Best Time Complexity:O(n)
	 Average Time Complexity:O(n^2)
	 Worst Time Complexity:O(n^2)
     
   Space Complexity
     No auxiliary space is required in Linear Search implementation.
	 Hence space complexity is:O(1)
*/

import java.util.Arrays;
import java.util.Scanner;

public class InsertionSort {
    public static int[] sort(int arr[]) {
        for (int i = 0; i < arr.length; i++) {
            int j = i - 1; // j will point to previous element
            int k = arr[i]; // k holds the value being sorted

            while (j >= 0 && k <= arr[j]) {
                arr[j + 1] = arr[j];
                j = j - 1;
            }

            arr[j + 1] = k;

        }
        return arr; //returns the sorted array

    }

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        int arr[] = new int[10];

        System.out.println("Enter Array Values: ");
        for (int i = 0; i < arr.length; i++) {
            arr[i] = sc.nextInt();
        }

        int a[] = new int[arr.length];

        a = Arrays.copyOf(sort(arr), arr.length); //copies the sorted array to another array

      	//sorted in ascending order
        System.out.println("Sorted Array:");
        for (int i = 0; i < a.length; i++) {
            System.out.print(+a[i] + " ");
        }
    }

}

Popularity 10/10 Helpfulness 2/10 Language java

Source: Grepper

Tags: insertion-sort inse

Link to this answer
Share Copy Link

Contributed on Aug 20 2022

Wild Wolverine

0 Answers Avg Quality 2/10

insertion sort java

Contents

More Related Answers

insertion sort java

Closely Related Answers

insertion sort java

Insertion sort in Java

Java Insertion Sort

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.