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substring with concatenation of all words

Sumit Rawal answered on August 17, 2022 Popularity 5/10 Helpfulness 2/10

answer substring with concatenation of all words

related Substring with Concatenation of All Words

substring with concatenation of all words

Comment

class Solution {
    private HashMap<String, Integer> wordCount = new HashMap<String, Integer>();
    private int n;
    private int wordLength;
    private int substringSize;
    private int k;
    
    private void slidingWindow(int left, String s, List<Integer> answer) {
        HashMap<String, Integer> wordsFound = new HashMap<>();
        int wordsUsed = 0;
        boolean excessWord = false;
        
        // Do the same iteration pattern as the previous approach - iterate
        // word_length at a time, and at each iteration we focus on one word
        for (int right = left; right <= n - wordLength; right += wordLength) {
            
            String sub = s.substring(right, right + wordLength);
            if (!wordCount.containsKey(sub)) {
                // Mismatched word - reset the window
                wordsFound.clear();
                wordsUsed = 0;
                excessWord = false;
                left = right + wordLength;
            } else {
                // If we reached max window size or have an excess word
                while (right - left == substringSize || excessWord) {
                    String leftmostWord = s.substring(left, left + wordLength);
                    left += wordLength;
                    wordsFound.put(leftmostWord, wordsFound.get(leftmostWord) - 1);

                    if (wordsFound.get(leftmostWord) >= wordCount.get(leftmostWord)) {
                        // This word was an excess word
                        excessWord = false;
                    } else {
                        // Otherwise we actually needed it
                        wordsUsed--;
                    }
                }
                
                // Keep track of how many times this word occurs in the window
                wordsFound.put(sub, wordsFound.getOrDefault(sub, 0) + 1);
                if (wordsFound.get(sub) <= wordCount.get(sub)) {
                    wordsUsed++;
                } else {
                    // Found too many instances already
                    excessWord = true;
                }
                
                if (wordsUsed == k && !excessWord) {
                    // Found a valid substring
                    answer.add(left);
                }
            }
        }
    }
    
    public List<Integer> findSubstring(String s, String[] words) {
        n = s.length();
        k = words.length;
        wordLength = words[0].length();
        substringSize = wordLength * k;
        
        for (String word : words) {
            wordCount.put(word, wordCount.getOrDefault(word, 0) + 1);
        }
        
        List<Integer> answer = new ArrayList<>();
        for (int i = 0; i < wordLength; i++) {
            slidingWindow(i, s, answer);
        }
        
        return answer;
    }
}

Popularity 5/10 Helpfulness 2/10 Language whatever

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Tags: concatenation substring whatever words

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Contributed on Oct 29 2022

Sumit Rawal

0 Answers Avg Quality 2/10

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Substring with Concatenation of All Words

Comment

class Solution {
public:
    vector<int> findSubstring(string s, vector<string>& words) {
        
    }
};

Popularity 7/10 Helpfulness 1/10 Language cpp

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Tags: c++ concatenation concat

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Contributed on Aug 17 2022

CodeBlack reactor

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Substring with Concatenation of All Words

Comment

class Solution {
    public List<Integer> findSubstring(String s, String[] words) {
        
    }
}

Popularity 3/10 Helpfulness 1/10 Language java

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Tags: concatenation java substring words

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Contributed on Aug 17 2022

CodeBlack reactor

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Substring with Concatenation of All Words

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/**
 * Note: The returned array must be malloced, assume caller calls free().
 */
int* findSubstring(char * s, char ** words, int wordsSize, int* returnSize){

}

Popularity 3/10 Helpfulness 1/10 Language c

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Tags: c concatenation substring words

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Contributed on Aug 17 2022

CodeBlack reactor

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Substring with Concatenation of All Words

Comment

public class Solution {
    public IList<int> FindSubstring(string s, string[] words) {
        
    }
}

Popularity 4/10 Helpfulness 1/10 Language csharp

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Tags: c# concatenation substring words

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Substring with Concatenation of All Words

Comment

/**
 * @param {string} s
 * @param {string[]} words
 * @return {number[]}
 */
var findSubstring = function(s, words) {
    
};

Popularity 3/10 Helpfulness 1/10 Language javascript

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Tags: concatenation javascript substring words

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Contributed on Aug 17 2022

CodeBlack reactor

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Substring with Concatenation of All Words

Comment

# @param {String} s
# @param {String[]} words
# @return {Integer[]}
def find_substring(s, words)
    
end

Popularity 4/10 Helpfulness 1/10 Language ruby

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Tags: concatenation ruby substring words

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Substring with Concatenation of All Words

Comment

class Solution {
    func findSubstring(_ s: String, _ words: [String]) -> [Int] {
        
    }
}

Popularity 3/10 Helpfulness 1/10 Language swift

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Tags: concatenation substring swift words

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

Substring with Concatenation of All Words

Comment

class Solution {

    /**
     * @param String $s
     * @param String[] $words
     * @return Integer[]
     */
    function findSubstring($s, $words) {
        
    }
}

Popularity 5/10 Helpfulness 1/10 Language php

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Tags: concatenation php substring words

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Contributed on Aug 17 2022

CodeBlack reactor

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Substring with Concatenation of All Words

Comment

function findSubstring(s: string, words: string[]): number[] {

};

Popularity 3/10 Helpfulness 1/10 Language typescript

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Tags: concatenation substring typescript words

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Contributed on Aug 17 2022

CodeBlack reactor

0 Answers Avg Quality 2/10

substring with concatenation of all words

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