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Pointers c++

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Professional Coder answered on September 12, 2021 Popularity 9/10 Helpfulness 1/10

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Pointers c++

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// This will explain how pointers are used
#include <iostream> 
using namespace std; 
int main() 
{     
  int a = 5;  //Declare and initialize a variable
  /*
  The following pointer declarations are all valid and they all are doing the same:
  Declaring a new pointer and initializing it with 0 (a non accessible memory address) for safety-reasons.
  int * b = 0;
  int* b = 0                 
  int *b = 0; // This is how its usually written.
  int *b; // <= this, however would cause "b" to point to some random address which might be unsafe.
  */
  int *b = 0; // Create a new pointer of type int and initialize it with 0

  cout << "\"b\" is initialized and now pointing to memory-address:  " << b << endl << endl;

  //Now make the pointer "point" to the address of a
  b = &a; //"b" now points to the address of "a"

  cout << "\"a\" is stored at memory-address:  " << &a << endl;
  cout << "\"b\" is stored at memory-address:  " << &b << endl;
  cout << "\"b\" is pointing to memory-address now:  " << b << endl << endl;

  cout << "The value of \"a\" is: " << a << endl;  // returns the value of a

  //the "*b" will get the value from the address b points to (the value of a)
  cout << "The value of the area \"b\" is pointing to is: " << *b << endl << endl << endl;

  //Now modify the value of the address "b" is pointing to...effectively changing the value of "a"     
  *b=10;

  cout << "\"a\" is still stored at memory-address:  " << &a << endl;
  cout << "\"b\" is still stored at memory-address:  " << &b << endl;
  cout << "\"b\" is still pointing to memory-address:  " << b << endl << endl;

  cout << "The value of \"a\" is now: " << a << endl;  // returns the value of a
  cout << "The value of the area \"b\" is pointing to is now: " << *b << endl << endl;

  return 0;        
}

Popularity 9/10 Helpfulness 1/10 Language cpp

Source: www.learn-cpp.org

Tags: c++ pointers

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Contributed on Nov 07 2022

Professional Coder

0 Answers Avg Quality 2/10

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pointer c++

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int myvar = 6;
int pointer = &myvar; // adress of myvar
int value = *pointer; // the value the pointer points to: 6

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Sep 12 2021

FireTower

0 Answers Avg Quality 2/10

c++ pointer

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Pointers are datatypes that point to a value of another
variable using its memory adress. Pointers are declared as following:
int* pointer;

The value of pointers is the adress of the variable. When someone
wishes to adress the value behind the adress, he can do it like this:
*pointer = newValue;

The *-operator (dereference operator) can also be read
as "value pointed to by". The example above could in that way be
read as "Value pointed to by pointer is now newValue".
Note that the asterisk (*) used when declaring a pointer only
means that it is a pointer (it is part of its type compound pecifier),
and should not be confused with the dereference operator.
  
You can assign the adress of variables to pointers:
int foo1 = 24;
int* pointer = &foo1;

The &-operator (adress-of-operator) can be read as "adress-of".
Therefore the line with our pointer declaration can be read like
"int-pointer with name pointer has now the value of the adress of foo1"

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: cplusplus.com

Tags: c++

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Contributed on Jun 28 2023

Distinct Deer

0 Answers Avg Quality 2/10

pointers in C++

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A pointer is a variable that points to a location in memory. Here is an example below:

#include <iostream>//For those unaware, the lib "iostream" stands for input output stream and is used mostly for stuff like cout or cin.
//int main() is the main function which will run upon running the exe file.
int main() {
	int x = 10;//The variable we are looking to point too
	int* xptr = &x;//using "&" you get the momory location of the variable x and you are telling xptr to point to x's location.
	std::cout<<xptr<<std::endl;//prints to location it's pointing too
	std::cout<<&x<<std::endl;//If you did it correctly it will output the same thing as xptr
	std::cout<<*xptr<<std::endl;//It will print the value(10) of the variable its pointing too. this is called derefrencing
	std::cout<<x;//It will print 10.
	return 0;
}

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Mar 20 2023

Wan Jun Yi

0 Answers Avg Quality 2/10

C/C++ Pointers

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int *p1;
int * p2;

Popularity 9/10 Helpfulness 3/10 Language c

Source: www.programiz.com

Tags: c pointers point

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Contributed on Apr 17 2022

Friendly Fish

0 Answers Avg Quality 2/10

pointers in c++

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#include <iostream>

using namespace std;

int main()
{
   int x=5;
   int *ptr=&x;
   cout<<&x<<endl;        //prints the address of the variable (x)
   cout<<ptr<<endl;       //prints the address of the variable (x)
   cout<<*ptr<<endl;      //prints the value of x(5)
   cout<<&ptr<<endl;      //prints the address of the pointer (ptr)
   
   
}

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Jun 22 2022

S.Y

0 Answers Avg Quality 2/10

pointer cpp

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type *ptr;   // Declare a pointer variable called ptr as a pointer of type
// or
type* ptr;
// or
type * ptr;  // I shall adopt this convention

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: www3.ntu.edu.sg

Tags: c++

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Contributed on Jul 26 2022

px4 firmware

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c++ fonksion pointer

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#include <stdio.h>
int f1(int x) { return x * 2; }
int f2(int x) { return x * 4; }

int main()
{
    int (*fptr1)(int) = &f1;
    fptr1 = &f2;
  	fptr1(3);
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: necatiergin2019.medium.com

Tags: c++

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Contributed on Nov 30 2021

Arrogant Ape

0 Answers Avg Quality 2/10

c++ pointers and functions

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#include <iostream>

using namespace std;

void increment(int *n){  		//declare argument of the functon as pointer
    *n+=1;
   cout<<"In function: "<<*n<<endl; 
}

int main()
{
   int x=5;			
   increment(&x);		//passing the address of the variable to the function
   cout<<"In main: "<<x<<endl;
   
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Jun 22 2022

S.Y

0 Answers Avg Quality 2/10

Pointers in c++

Comment

int x = 2;
int *y = &x;

cout << *y;

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Apr 18 2022

Msk SK

0 Answers Avg Quality 2/10

why do we use pointers in c++

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//why do we use pointers:
1)pass values by refrence to a function
2)return multiple values from a function
3)use pointers in combinational with arrays
4)dynamic memory allocation
5)use pointers in a base class in order to access object of derived class (Smart pointers)

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Jun 23 2022

S.Y

0 Answers Avg Quality 2/10

Pointers c++

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