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#!/bin/bash NAME=($(getent passwd | cut -d

Tristan Coates answered on November 10, 2022 Popularity 1/10 Helpfulness 1/10

answer #!/bin/bash NAME=($(getent passwd | cut -d

#!/bin/bash NAME=($(getent passwd | cut -d

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cat ./test.sh 
#!/bin/bash

UNAME=${1} #set arg to var UNAME
if [ -z ${UNAME} ]; then #if no argument is provided; then display this
    echo "Not enough arguments provided."
    echo "USAGE: $0 <user_name>" 
    exit 1
fi
if grep ${UNAME} /etc/passwd >/dev/null; then #if UNAME exists then display info below
    echo "-------------------------------------------"
    echo "Username:       $(awk -F ':' -v uname=${UNAME} '$0 ~ uname {print $1}' /etc/passwd)"
    echo "User ID (UID):  $(awk -F ':' -v uname=${UNAME} '$0 ~ uname {print $3}' /etc/passwd)"
    echo "Group ID (GID): $(awk -F ':' -v uname=${UNAME} '$0 ~ uname {print $4}' /etc/passwd)"
    echo "User info:      $(awk -F ':' -v uname=${UNAME} '$0 ~ uname {print $5}' /etc/passwd)"
    echo "Home directory: $(awk -F ':' -v uname=${UNAME} '$0 ~ uname {print $6}' /etc/passwd)"
    echo "Command shell:  $(awk -F ':' -v uname=${UNAME} '$0 ~ uname {print $7}' /etc/passwd)"
    echo "-------------------------------------------"
else #if UNAME is nonexistant then display this error message
    echo "-------------------------------------------"
    echo "\"${UNAME}\" does not exist."
    echo "-------------------------------------------"
fi

Popularity 1/10 Helpfulness 1/10 Language shell

Source: stackoverflow.com

Tags: cut passwd shell

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Contributed on Nov 10 2022

Tristan Coates

0 Answers Avg Quality 2/10

#!/bin/bash NAME=($(getent passwd | cut -d

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