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sorted python lambda

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Ashamed Addax answered on June 23, 2020 Popularity 9/10 Helpfulness 7/10

answer sorted python lambda

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sorted python lambda

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lst = [('candy','30','100'), ('apple','10','200'), ('baby','20','300')]
lst.sort(key=lambda x:x[1])
print(lst)

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Source: stackoverflow.com

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Contributed on Jun 23 2020

Ashamed Addax

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a = ["tim", "bob", "anna", "steve", "john"]

# sorts the list by the first letter of each name
b = sorted(a, key=lambda x : x[0])
# x = each of the values in the list a

# sorts the list by length FIRST, then alphabetical order SECOND
c = sorted(a, key=lambda x : (len(x), x))

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Contributed on Nov 10 2021

JessiCoder

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sorted lambda

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sorted(student_tuples, key=lambda student: student[2])

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Source: Grepper

Tags: lambda la

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Contributed on Apr 21 2021

Serhii

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