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Amazon.Lambda.APIGatewayEvents

bdshanto answered on December 6, 2022 Popularity 2/10 Helpfulness 1/10

answer Amazon.Lambda.APIGatewayEvents

Amazon.Lambda.APIGatewayEvents

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public async Task<APIGatewayProxyResponse> LambdaHandler(
    APIGatewayProxyRequest request, 
    ILambdaContext context)
{
    var response = new APIGatewayProxyResponse {
        Headers = new Dictionary<string, string> {
            { "Access-Control-Allow-Origin", "*" },
            { 
                "Access-Control-Allow-Headers", 
                "Origin, X-Requested-With, Content-Type, Accept" 
            }
        }
    };

    string contentType = null;
    request.Headers?.TryGetValue("Content-Type", out contentType);

    switch (request.HttpMethod) {
        case "GET":
            context.Logger.LogLine($"Get Request: {request.Path}\n");
            response.StatusCode = (int)HttpStatusCode.OK;
            response.Body = "{ \"message\": \"Hello AWS Serverless\" }";
            response.Headers["Content-Type"] = "application/json";
            break;
        case "POST":
            context.Logger.LogLine($"Post Request: {request.Path}\n");
            if (!String.IsNullOrEmpty(contentType)) {
                context.Logger.LogLine($"Content type: {contentType}");
            }
            context.Logger.LogLine($"Body: {request.Body}");
            response.StatusCode = (int)HttpStatusCode.OK;
            break;
        case "PUT":
            context.Logger.LogLine($"Put Request: {request.Path}\n");
            if (!String.IsNullOrEmpty(contentType)) {
                context.Logger.LogLine($"Content type: {contentType}");
            }
            context.Logger.LogLine($"Body: {request.Body}");
            response.StatusCode = (int)HttpStatusCode.OK;
            break;
        case "DELETE":
            context.Logger.LogLine($"Delete Request: {request.Path}\n");
            response.StatusCode = (int)HttpStatusCode.OK;
            break;
        default:
            context.Logger.LogLine(
                $"Unrecognized verb {request.HttpMethod}\n"
            );
            response.StatusCode = (int)HttpStatusCode.BadRequest;
            break;
    }

    return response;
}

Popularity 2/10 Helpfulness 1/10 Language whatever

Source: aws.amazon.com

Tags: whatever

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Contributed on Dec 06 2022

bdshanto

0 Answers Avg Quality 2/10

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