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java spring get file via url

Singh99 answered on December 7, 2022 Popularity 4/10 Helpfulness 3/10

answer java spring get file via url

java spring get file via url

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// this my reset call

  @GetMapping("/files/{filename:.+}")
    @ResponseBody
    public ResponseEntity<Resource> getFile(@PathVariable String filename) {
        Resource file = storageService.load(filename);
        return ResponseEntity.ok()
                .header(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename=\"" + file.getFilename() + "\"").body(file);
    }

    @PostMapping("/upload")
    public ResponseEntity<JSONObject> uploadFile(@RequestParam("file") MultipartFile file, @RequestHeader HttpHeaders headers) {
        JSONObject message = new JSONObject();
        String email = helpers.GetUserFromToken(headers); //this is my stuff for JWT
        System.out.println(file);
        String filename = file.getOriginalFilename();
        String extension =filename.substring(filename.lastIndexOf(".") + 1);
        Long fileSize =  file.getSize();

        String[] nameArray = new String[]{"jpg", "png", "jpeg"};
        List<String>  array = new ArrayList<String>(Arrays.asList(nameArray));

        if(array.contains(extension.toLowerCase()) && (fileSize/1025 < 500)){ //Validation
            try {
                String FileName =  storageService.save(file); //save in Folder Watch the function blow class named with save method
                message.put("status","success");
                message.put("msg","Uploaded the file successfully: " + FileName);
                userServices.UpdateProfilePic(email,FileName); // save in DATABASE
                return ResponseEntity.status(HttpStatus.OK).body(message);
            } catch (Exception e) {
                message.put("status","error");
                message.put("msg","Could not upload the file: " + file.getOriginalFilename() + ". Error: " + e.getMessage());
                return ResponseEntity.status(HttpStatus.EXPECTATION_FAILED).body(message);
            }

        }else{
            message.put("status","error");
            message.put("msg","incorrect file format or file size");
            if(!array.contains(extension.toLowerCase())){
                message.put("format_allowed","jpg,png,jpeg");
            }
            if( (fileSize/1025 > 500)){
                message.put("file_size","the file Size Should be blow 500kb");
            }
            return ResponseEntity.status(HttpStatus.NOT_FOUND).body(message);
        }

    }

// is my main Storage file which handles everything


package it.XYZ.storage; // change as per your project

import org.springframework.core.io.Resource;
import org.springframework.core.io.UrlResource;
import org.springframework.stereotype.Service;
import org.springframework.web.multipart.MultipartFile;

import java.io.File;
import java.net.MalformedURLException;
import java.nio.file.FileAlreadyExistsException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;

@Service
public class StorageServiceImp implements StorageService{
    private final Path root = Paths.get("uploads");

    @Override
    public String save(MultipartFile file) {
        String newName = "";
        try {
            // get the file and change with current dateTime
             String filename = file.getOriginalFilename();
             String extension =filename.substring(filename.lastIndexOf(".") + 1);
              newName = String.valueOf(System.currentTimeMillis()).concat("."+extension); // rewrite name of file 
            // get the file and change with current dateTime

            Files.copy(file.getInputStream(), this.root.resolve(newName));
        } catch (Exception e) {
            if (e instanceof FileAlreadyExistsException) {
                throw new RuntimeException("A file of that name already exists.");
            }

            throw new RuntimeException(e.getMessage());
        }
        return newName;
    }

    @Override
    public Resource load(String filename) {
        try {
            Path file = root.resolve(filename);
            Resource resource = new UrlResource(file.toUri());

            if (resource.exists() || resource.isReadable()) {
                return resource;
            } else {
                throw new RuntimeException("Could not read the file!");
            }
        } catch (MalformedURLException e) {
            throw new RuntimeException("Error: " + e.getMessage());
        }
    }

    @Override
    public void deleteFile(String FileName) {
        try {
            File existingFile = new File(this.root.resolve(FileName).toUri());

            if (existingFile.exists() && existingFile.isFile()) {
                existingFile.delete();
            }
        }catch (Exception e){
            
        }

    }
}

Popularity 4/10 Helpfulness 3/10 Language java

Source: Grepper

Tags: file get java spring url

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Contributed on Dec 07 2022

Singh99

0 Answers Avg Quality 2/10

java spring get file via url

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