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Java Program to find deficient number

Anjali Sharma answered on January 5, 2023 Popularity 1/10 Helpfulness 1/10

answer Java Program to find deficient number

Java Program to find deficient number

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public class Main 
{
  static int divsum(int n) 
  {
    int sum = 0;
    for (int i = 1; i <= (Math.sqrt(n)); i++) {
      if (n % i == 0) {
 
        if (n / i == i) {
          sum = sum + i;
        } else {
          sum = sum + i;
          sum = sum + (n / i);
        }
      }
    }
    return sum;
  }
 
  static boolean isDeficientNumber(int n) 
  {
    return (divsum(n) < (2 * n));
  }
 
  public static void main(String args[]) {
    System.out.println("21 is deficient number : " + isDeficientNumber(21));
    System.out.println("20 is deficient number : " + isDeficientNumber(20));
  }
}

Popularity 1/10 Helpfulness 1/10 Language java

Source: howtodoinjava.com

Tags: find java

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