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newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])
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x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
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>>> d = {"aa": 3, "bb": 4, "cc": 2, "dd": 1}
>>> for k in sorted(d, key=d.get, reverse=True):
k, d[k]
('bb', 4)
('aa', 3)
('cc', 2)
('dd', 1)
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>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
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# How to sort a Python dict by value
# (== get a representation sorted by value)
>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1}
>>> sorted(xs.items(), key=lambda x: x[1])
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]
# Or:
>>> import operator
>>> sorted(xs.items(), key=operator.itemgetter(1))
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]
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A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A, key=A.get)}
output:
{4: -20, 1: 2, -1: 4}
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d = {'one':1,'three':3,'five':5,'two':2,'four':4}
a = sorted(d.items(), key=lambda x: x[1])
print(a)