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insertion in singly linked list in c++

Muhammad Rayyan answered on October 29, 2022 Popularity 8/10 Helpfulness 2/10

answer insertion in singly linked list in c++

insertion in singly linked list in c++

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struct Node
{
    int data;
    Node *next;
    Node(int val)
    {
        data = val;
        next = NULL;
    }
};
void insertAtTail(Node *&head, int val)
{
    Node *n = new Node(val);
    Node *temp = head;
    if (temp == NULL)
    {
        head = n;
        return;
    }
    while (temp->next != NULL)
    {
        temp = temp->next;
    }
    temp->next = n;
}
void insertAtHead(Node *&head, int val)
{
    Node *n = new Node(val);
    n->next = head;
    head = n;
}
void insertAtPos(Node *&head, int val, int pos)
{
    Node *n = new Node(val);
    Node *temp = head;
    Node *temp1 = NULL;
    int count = 0;
    while (temp != NULL && count != pos)
    {
        count++;
        temp1 = temp;
        temp = temp->next;
    }
    temp1->next = n;
    n->next = temp;
}

// In main function  use above functions like this
 Node *head = NULL;
    insertAtTail(head, 1);
    insertAtTail(head, 2);
    insertAtTail(head, 3);

Popularity 8/10 Helpfulness 2/10 Language cpp

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Contributed on Feb 08 2023

Muhammad Rayyan

0 Answers Avg Quality 2/10

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Insertion In Linked List C++

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// All Three Conditons
// -> Insert at head
// -> Insert at middle
// -> Insert at tail

void InsertAtTail(Node *&head, Node *&tail, int data)
{
	// If Linked List is empty //
	if (tail == NULL)
	{
		// Creating a new node //
		Node *newNode = new Node(data);
		// if LL has only one node then head and tail will be the same node //
		head = newNode;
		tail = newNode;
		return;
	}
	Node *newNode = new Node(data);
	// assign next node of tail to new node //
	tail->next = newNode;
	// replacing tail with new node as it is the Last node (Tail) now //
	tail = newNode;
}
void InsertAtHead(Node *&head, Node *&tail, int data)
{
	// If Linked List is empty //
	if (head == NULL)
	{
		// Creating a new node //
		Node *newNode = new Node(data);
		// if LL has only one node then head and tail will be the same node //
		head = newNode;
		tail = newNode;
		// returning from the function //
		return;
	}
	// Create a new node //
	Node *newNode = new Node(data);
	// assign next node to head //
	newNode->next = head;
	// replace head with new node //
	head = newNode;
}
void InsertAtMiddle(Node* &head , Node* &tail , int data , int positon){
	int len = FindLength(head);

	if(positon==0){
		InsertAtHead(head,tail,data);
		return;
	}
    else if(positon==len){
		InsertAtTail(head,tail,data);
		return;
	}
	int i = 1;
	Node* prev = head;
	while(i < positon){
        prev = prev ->next;
		i++;
	}
    Node *cur = prev -> next;
	Node* newNode = new Node(data);
	prev ->next = newNode;
	newNode ->next = cur; 
}

Popularity 8/10 Helpfulness 4/10 Language cpp

Source: Grepper

Tags: c++ insertion in

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Contributed on Sep 08 2023

khair muhammad

0 Answers Avg Quality 2/10

linked list insertion

Comment

/*
class Node{
    int data;
    Node next;
    
    Node(int x){
        data = x;
        next = null;
    }
}
*/
class Solution1
{
    //Function to insert a node at the beginning of the linked list.
    Node insertAtBeginning(Node head, int x)
    {
        // code here
        Node n = new Node(x);
        n.next=head;
        head = n;
        return head;
    }

    //Function to insert a node at the end of the linked list.
    Node insertAtEnd(Node head, int x)
    {
        // code here
        Node node = new Node(x);
        if(head == null)
        {
            head = node;
            return head;
        }
        Node temp = head;
        while(temp.next!=null)
        {
            temp = temp.next;
        }
        temp.next = node;
        return head;
    }
}

Popularity 9/10 Helpfulness 2/10 Language whatever

Source: Grepper

Tags: insertion inse

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Contributed on Oct 29 2022

Sumit Rawal

0 Answers Avg Quality 2/10

insertion in singly linked list in c++

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