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how to return the transpose of a matrix in javascript

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Enchanting Earthworm answered on June 24, 2020 Popularity 5/10 Helpfulness 1/10

answer how to return the transpose of a matrix in javascript

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how to return the transpose of a matrix in javascript

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// m has to be a 2d matrix
function matrix_transpose(m) {
    var rows = m.length
    var cols = m[0].length
    var result = new Array(cols);
  
    for (let i = 0; i < cols; i++)
        result[i] = new Array(rows)

    for(var i = 0; i < m[0].length; i++) {
        for(var j = 0; j < m.length; j++) {
            result[i][j] = m[j][i]
        }
    }

    return result
}

This is a solution for N x M matrices.

Popularity 5/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript matrix return transpose

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Contributed on Feb 19 2023

Enchanting Earthworm

0 Answers Avg Quality 2/10

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//One-liners inspired by Fawad Ghafoor and Óscar Gómez Alcañiz

function transpose(matrix) {
  return matrix[0].map((col, i) => matrix.map(row => row[i]));
}

function transpose(matrix) {
  return matrix[0].map((col, c) => matrix.map((row, r) => matrix[r][c]));
}
//Functional approach style with reduce by Andrew Tatomyr

function transpose(matrix) {
  return matrix.reduce((prev, next) => next.map((item, i) =>
    (prev[i] || []).concat(next[i])
  ), []);
}
//Lodash/Underscore by marcel

function tranpose(matrix) {
  return _.zip(...matrix);
}

// Without spread operator.
function transpose(matrix) {
  return _.zip.apply(_, [[1,2,3], [1,2,3], [1,2,3]])
}
Even simpler Lodash/Underscore solution by Vigrant

_.unzip(matrix);
Vanilla approach

function transpose(matrix) {
  const rows = matrix.length, cols = matrix[0].length;
  const grid = [];
  for (let j = 0; j < cols; j++) {
    grid[j] = Array(rows);
  }
  for (let i = 0; i < rows; i++) {
    for (let j = 0; j < cols; j++) {
      grid[j][i] = matrix[i][j];
    }
  }
  return grid;
}
//Vanilla in-place ES6 approach inspired by Emanuel Saringan

function transpose(matrix) {
  for (var i = 0; i < matrix.length; i++) {
    for (var j = 0; j < i; j++) {
      const temp = matrix[i][j];
      matrix[i][j] = matrix[j][i];
      matrix[j][i] = temp;
    }
  }
}

// Using destructing
function transpose(matrix) {
  for (var i = 0; i < matrix.length; i++) {
    for (var j = 0; j < i; j++) {
      [matrix[i][j], matrix[j][i]] = [matrix[j][i], matrix[i][j]];
    }
  }
}

Popularity 9/10 Helpfulness 10/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Nov 21 2021

code fighter

0 Answers Avg Quality 2/10

transpose of the matrix in javascript

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class Solution {
    solve(matrix) {
        let arr=[];
        for(let i=0;i<matrix.length;i++){
            arr.push([])
            for(let j=0;j<matrix.length;j++){
                arr[i].push(matrix[j][i])
            }
        }
        return arr
    }
}

Popularity 9/10 Helpfulness 5/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Jun 24 2020

Courageous Caiman

0 Answers Avg Quality 2/10

how to return the transpose of a matrix in javascript

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