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Implementing LogAccessFilter

Pragya Keshap answered on February 21, 2023 Popularity 1/10 Helpfulness 1/10

answer Implementing LogAccessFilter

Implementing LogAccessFilter

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import org.apache.logging.log4j.LogManager;
import org.apache.logging.log4j.Logger;

import javax.servlet.annotation.WebFilter;
import javax.servlet.http.HttpServletRequest;
import java.io.IOException;
import java.util.Date;

@WebFilter(filterName = "LogAccess", urlPatterns = "/*")
public class LogAccessFilter implements javax.servlet.Filter {

private static Logger logger = LogManager.getLogger(LogAccess.class);

    public void destroy() {
    }

public void doFilter(javax.servlet.ServletRequest req, 
    javax.servlet.ServletResponse resp, javax.servlet.FilterChain 
    chain) throws javax.servlet.ServletException, IOException {

//Gets the initial date of request.
Date dateInitRequest = new Date();

//Get IP of Client that sent a resquest.
String ip = ((HttpServletRequest)req).getRemoteAddr();

//Following to next filter. If none next filter exist, follows   
        //for main logic.
chain.doFilter(req, resp);

//Gets the end date of request.
Date dateEndRequest = new Date();

//Logging the informations of IP and access time.
logger.info("IP: "+ip +" Access time : "
+ Long.toString(dateEndRequest.getTime() 
                              - dateInitRequest.getTime())
                              + " ms");

}

public void init(javax.servlet.FilterConfig config) throws 
    javax.servlet.ServletException {

    }

}

Popularity 1/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: java

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Contributed on Feb 21 2023

Pragya Keshap

0 Answers Avg Quality 2/10

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