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// Assuming the array is all integers,
// Math.min works as long as you use the spread operator(...).
let arrayOfIntegers = [9, 4, 5, 6, 3];
let min = Math.min(arrayOfIntegers);
// => 3
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const array = [4, 2, 8, 1];
const minimum = Math.min(array);
console.log(minimum);
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var min = Math.min.apply(null, arr),
max = Math.max.apply(null, arr);
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function findMinMax(arr) {
if (arr.length === 0) {
return "Array is empty.";
}
let min = arr[0];
let max = arr[0];
for (let i = 1; i < arr.length; i++) {
if (arr[i] < min) {
min = arr[i];
}
if (arr[i] > max) {
max = arr[i];
}
}
return { min, max };
}
// Example usage:
const numbers = [11, 5, 8, 3, 20, 16];
const result = findMinMax(numbers);
console.log(result); // Output: { min: 3, max: 20 }
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// find minimum value in array using javascript
let arrVal = [23, 34, 56, 67, 4, 57, 8];
let ans = arrVal[0];
for (let i = 1; i < arrVal.length; i++) {
if (ans > arrVal[i]) {
ans = arrVal[i];
}
}
console.log(ans); // 4
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//create array list
var myArray = [1, 5, 6, 2, 3];
// get min value
var minVal = Math.min.apply(null, myArray);
console.log(minVal)
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public class ArrayMin {
public static void main(String[] args) {
double[] numbers = new double[4];
numbers[0] = 1.7;
numbers[1] = 1.9;
numbers[2] = 5.7;
numbers[3] = 6;
double min = numbers[0];
for (int i = 0; i < numbers.length; i++) {
if(numbers[i] < min) {
min = numbers[i];
}
}
System.out.println(min);
}
}