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Paul Negedu answered on August 30, 2021 Popularity 8/10 Helpfulness 1/10

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#Implement, time & rank 13 sorting algorithms in python
#https://github.com/paulnegz/sorts-py/tree/main

def quick_sort(array :list)->list:
    def _quick_sort(array :list)->list:
        if len(array)<=1: return array
        
        pivot, is_bigger = array.pop(), lambda x: x>pivot
        left_partition = _quick_sort([x for x in array if not is_bigger(x)])
        right_partition = _quick_sort([x for x in array if is_bigger(x)])
        return [*left_partition, pivot, *right_partition]
    return _quick_sort(array)

def bubble_sort(array :list)->list:
    for y in range(1, len(array)):
        swap: bool = False
        for x in range(1,len(array)-(y-1)):
            if array[x]<array[x-1]:
                array[x],array[x-1], swap = array[x-1],array[x], True
        if not swap: break
    return array 
  
  def radix_sort(array :list)->list:
    base, max_length = 10, len(str(max(array)))
    for n in range(max_length):
        bucket=[[] for _ in range(base)]
        for item in array: bucket[item//base**n%base].append(item)
        flat_map = lambda arr: reduce(lambda acc, curr: [*acc,*curr], arr)
        array = flat_map(bucket)
    return array
  
  def selection_sort(array :list)->list:
    for idx_y, _ in enumerate(array):
        min_idx = idx_y
        for idx in range(idx_y,len(array)):
            if array[idx] < array[min_idx]: min_idx = idx
        array[min_idx], array[idx_y] = array[idx_y], array[min_idx]
    return array
  
  def _shell_sort(array: list)->list:
    LENGTH, gap= len(array), len(array)//2
    while gap>0:
        for j in range(gap, LENGTH):
            i=j-gap 
            while i>=0:
                if array[i+gap]>array[i]: break
                else: array[i+gap],array[i]=array[i],array[i+gap]
                i=i-gap 
        gap=gap//2
    return array
  
  def bucket_sort(array :list)->list:
    BUCKET_SIZE = ceil(len(array)**(3/4))
    min_val, max_val = min(array), max(array)

    RANGE = (max_val-min_val+1)/BUCKET_SIZE
    bucket = [[] for _ in range(BUCKET_SIZE)]
    
    get_idx = lambda num: int((num-min_val)/RANGE)
    for num in array: bucket[get_idx(num)].append(num)
    for x in bucket: _insertion_sort(x)
    flat_map = lambda arr: reduce(lambda acc, curr: [*acc,*curr], arr)
    return flat_map(bucket)

Popularity 8/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: python sorting

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Contributed on Jun 25 2023

Paul Negedu

0 Answers Avg Quality 2/10

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#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
    int x = time(0);
    srand(x);
    const int size = 10;
    int arr[size];
    for (int i = 0; i < size; i++)
    {
        arr[i] = (rand() % 10) + 1;
    }
    for (int i = 0; i < size; i++)
    {
        cout << arr[i] << " ";
    }
    for (int i = 1; i < size; i++)
    {
        int temp;
        if (arr[i] < arr[i - 1])
        {
            temp = arr[i];
            int j = i;
            do
            {
                arr[j] = arr[j - 1];
                j--;
            } while (j > 0 && arr[j - 1] > temp);
            arr[j] = temp;
        }
    }
    cout << endl;
    for (int i = 0; i < size; i++)
    {
        cout << arr[i] << " ";
    }

    return 0;
}

Popularity 10/10 Helpfulness 1/10 Language cpp

Source: salikcpp.netlify.app

Tags: c++

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Contributed on Oct 04 2022

Muhib Arshad

0 Answers Avg Quality 2/10

sorting

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{% assign sorted_products = collection.products | sort: SELECT_CHOICE_HERE %}

Popularity 9/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: sorting

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Contributed on Jun 07 2022

Poor Porpoise

0 Answers Avg Quality 2/10

sorting

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<div class="sort-collection-by">
<label for="sort-by">Sort by</label> 
<select id="sort-by">
    <option value="manual">Featured</option>
    <option value="price-ascending">Price: Low to High</option>
    <option value="price-descending">Price: High to Low</option>
    <option value="title-ascending">A-Z</option>
    <option value="title-descending">Z-A</option>
    <option value="created-ascending">Oldest to Newest</option>
    <option value="created-descending">Newest to Oldest</option>
    <option value="best-selling">Best Selling</option>
</select>
</div>

Popularity 9/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: sorting

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Contributed on Jun 07 2022

Poor Porpoise

0 Answers Avg Quality 2/10

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let numbers = [1, 4, 1, 2, 7, 5, 2];
let count = [];
let output =[];
let i = 0;
let max = Math.max(...numbers);

// initialize counter
for (i = 0; i <= max; i++) {
  count[i] = 0;
}

// initialize output array
for (i = 0; i < numbers.length; i++) {
  output[i] = 0;
}

for (i = 0; i < numbers.length; i++) {
  count[numbers[i]]++;
}

for (i = 1; i < count.length; i++) {
  count[i] += count[i-1];
}

for (i = numbers.length - 1; i >= 0; i--) { 
  output[--count[numbers[i]]] = numbers[i];
}

// output sorted array
for (i = 0; i < output.length; i++) {
  console.log(output[i]);
}

Popularity 9/10 Helpfulness 1/10 Language whatever

Source: www.freecodecamp.org

Tags: sorting

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Contributed on Jul 19 2022

Abdalraof Benaesha

0 Answers Avg Quality 2/10

sql server CREATE PROCEDURE permission denied in database

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GRANT CREATE VIEW TO [UserName];
GRANT CREATE PROCEDURE TO [UserName];
GRANT ALTER ON SCHEMA::[dbo] TO [UserName];

Popularity 1/10 Helpfulness 1/10 Language sql

Source: Grepper

Tags: database permission-denied procedure sql sql-server

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Contributed on Nov 20 2024

Have You Googled it

0 Answers Avg Quality 2/10

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(function(){
	var arrayNumb = [2, 8, 15, 16, 23, 42];
	arrayNumb.sort();
	console.log(arrayNumb);
})();

Popularity 2/10 Helpfulness 1/10 Language whatever

Source: github.com

Tags: sorting whatever

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Contributed on Nov 21 2024

Repulsive Rhinoceros

0 Answers Avg Quality 2/10

Sorting

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Bubble Sort, Selection sort, Merge sort

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Source: Grepper

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Contributed on Aug 30 2021

Donald Duck

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-2

jQuery('#sort-by').bind('change', function() {
  Shopify.queryParams.sort_by = jQuery(this).val();
  location.search = jQuery.param(Shopify.queryParams).replace(/\+/g, '%20');
});

Popularity 9/10 Helpfulness 1/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Jun 07 2022

Poor Porpoise

0 Answers Avg Quality 2/10

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