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Can you write Python code to implement this?

Green Team answered on June 26, 2023 Popularity 7/10 Helpfulness 1/10

answer Can you write Python code to implement this?

Can you write Python code to implement this?

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from collections import defaultdict

def dfs(graph, vertex, visited, stack):
    visited[vertex] = True
    for neighbor in graph[vertex]:
        if not visited[neighbor]:
            dfs(graph, neighbor, visited, stack)
    stack.append(vertex)

def get_sink_components(graph):
    # Step 1: Reverse the edges of the graph to obtain GR
    reversed_graph = defaultdict(list)
    for vertex in graph:
        for neighbor in graph[vertex]:
            reversed_graph[neighbor].append(vertex)

    # Step 2: Run DFS on GR to determine finishing times
    visited = defaultdict(bool)
    stack = []
    for vertex in reversed_graph:
        if not visited[vertex]:
            dfs(reversed_graph, vertex, visited, stack)

    # Step 4: Sort vertices based on finishing times
    sorted_vertices = sorted(stack, reverse=True)

    # Step 5: Identify sink components in G
    sink_components = []
    visited = defaultdict(bool)
    for vertex in sorted_vertices:
        if not visited[vertex]:
            component = []
            dfs(graph, vertex, visited, component)
            sink_components.append(component)

    return sink_components

# Example usage:
# Define the graph as an adjacency list
graph = {
    1: [2],
    2: [3, 4],
    3: [],
    4: [5],
    5: [],
    6: [4, 7],
    7: [],
    8: [6, 9],
    9: []
}

sink_components = get_sink_components(graph)
print("Sink components of G:")
for component in sink_components:
    print(component)

Popularity 7/10 Helpfulness 1/10 Language python

Source: chat.openai.com

Tags: python

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Contributed on Jun 26 2023

Green Team

0 Answers Avg Quality 2/10

Can you write Python code to implement this?

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