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longest common subsequence (str, str)

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Mridu Pawan answered on April 5, 2022 Popularity 10/10 Helpfulness 2/10

answer longest common subsequence (str, str)

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longest common subsequence (str, str)

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int LongestRepeatingSubsequence(string str){
  // Code here
  int n=str.length();

  vector<int> prev(n+1,0), cur(n+1,0);

  for(int i=1;i<=n;i++){
    for(int j=1;j<=n;j++){
      if(str[i-1]==str[j-1])cur[j]=1+prev[j-1];
      else cur[j]=max(cur[j-1], prev[j]);
    }
    prev=cur;
  }
  return cur[n];
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++ subsequence

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Contributed on Jul 18 2023

Mridu Pawan

0 Answers Avg Quality 2/10

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longest common substring

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int findLength(vector<int>& nums1, vector<int>& nums2) 
    {
        int n=nums1.size();
        int m=nums2.size();
        vector<vector<int>>dp(n+1,vector<int>(m+1));
        for(int i=0;i<=n;i++)
        {
            dp[i][0]=0;
        }
        for(int i=0;i<=m;i++)
        {
            dp[0][i]=0;
        }
        int ans=0;
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=m;j++)
            {
                if(nums1[i-1]==nums2[j-1])
                {
                    dp[i][j]=1+dp[i-1][j-1];
                    ans=max(ans,dp[i][j]);
                }
                else
                {
                    dp[i][j]=0;
                }
            }
        }
        return ans;
    }

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Apr 05 2022

ujjwal sotra

0 Answers Avg Quality 2/10

print longest common subsequence

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#include <bits/stdc++.h>

using namespace std;

void lcs(string s1, string s2) {

  int n = s1.size();
  int m = s2.size();

  vector < vector < int >> dp(n + 1, vector < int > (m + 1, 0));
  for (int i = 0; i <= n; i++) {
    dp[i][0] = 0;
  }
  for (int i = 0; i <= m; i++) {
    dp[0][i] = 0;
  }

  for (int ind1 = 1; ind1 <= n; ind1++) {
    for (int ind2 = 1; ind2 <= m; ind2++) {
      if (s1[ind1 - 1] == s2[ind2 - 1])
        dp[ind1][ind2] = 1 + dp[ind1 - 1][ind2 - 1];
      else
        dp[ind1][ind2] = 0 + max(dp[ind1 - 1][ind2], dp[ind1][ind2 - 1]);
    }
  }

  int len = dp[n][m];
  int i = n;
  int j = m;

  int index = len - 1;
  string str = "";
  for (int k = 1; k <= len; k++) {
    str += "$"; // dummy string
  }

  while (i > 0 && j > 0) {
    if (s1[i - 1] == s2[j - 1]) {
      str[index] = s1[i - 1];
      index--;
      i--;
      j--;
    } else if (s1[i - 1] > s2[j - 1]) {
      i--;
    } else j--;
  }
  cout << str;
}

int main() {

  string s1 = "abcde";
  string s2 = "bdgek";

  cout << "The Longest Common Subsequence is ";
  lcs(s1, s2);
}

Popularity 8/10 Helpfulness 2/10 Language cpp

Source: takeuforward.org

Tags: c++ subsequence subseque

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Contributed on Mar 27 2024

Pranay Dubey

0 Answers Avg Quality 2/10

longest common subsequence

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class Solution
{
    
    //Function to find the length of longest common subsequence in two strings.
    static int lcs(int x, int y, String s1, String s2)
    {
         int dp[][] = new int[x+1][y+1];
         for(int i=0;i<=x;i++)
         {
             for (int j=0;j<=y;j++)
             {
                 dp[i][j]=-1;
             }
         } 
        return lcshelper(x,y,s1,s2, dp);
    }
    
   static int lcshelper(int m,int n,String x, String y, int[][] dp)
    {
        
        if(m==0 || n==0)
            return 0;
        
        if (dp[m][n]!= -1)
            return dp[m][n];
            
        if (x.charAt(m-1)==y.charAt(n-1))
            dp[m][n] = 1+lcshelper(m-1,n-1,x,y, dp);
        else
        dp[m][n]= Math.max(lcshelper(m-1,n,x,y,dp), lcshelper(m,n-1,x,y,dp));
        return dp[m][n];
    }
    
}

Popularity 10/10 Helpfulness 1/10 Language whatever

Source: Grepper

Tags: subsequence subs

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Contributed on Oct 19 2022

Sumit Rawal

0 Answers Avg Quality 2/10

longest common subsequence (str, str)

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