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java random String

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Cabs answered on July 16, 2020 Popularity 7/10 Helpfulness 4/10

answer java random String

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java random String

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// Import required packages
import java.util.Random;

// Generate a random alphanumeric string
Random random = new Random();
String generatedString = random.ints(48, 122) 
  .filter(i -> (i <= 57 || i >= 65) && (i <= 90 || i >= 97))
  .limit(10)
  .collect(StringBuilder::new, StringBuilder::appendCodePoint, StringBuilder::append)
  .toString();

Popularity 7/10 Helpfulness 4/10 Language java

Source: Grepper

Tags: java random string

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Contributed on Jul 26 2023

Cabs

0 Answers Avg Quality 2/10

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generate random string in java

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import java.util.Random;

public class Generator {
	public static String generateRandomPassword(int len) {
		String chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijk"
          +"lmnopqrstuvwxyz!@#$%&";
		Random rnd = new Random();
		StringBuilder sb = new StringBuilder(len);
		for (int i = 0; i < len; i++)
			sb.append(chars.charAt(rnd.nextInt(chars.length())));
		return sb.toString();
	}
}

Popularity 10/10 Helpfulness 9/10 Language java

Source: Grepper

Tags: generate generat

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Contributed on Jul 16 2020

Vishal

0 Answers Avg Quality 2/10

java random string

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public static String randomString() {
    return UUID.randomUUID().toString();
}

Popularity 9/10 Helpfulness 6/10 Language java

Source: Grepper

Tags: java random r

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Contributed on Sep 03 2022

3oly

0 Answers Avg Quality 2/10

java random string

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public static String getRandomString(int size) {
  	// The string that we will return
	String rand = "";
  	// The chars that are used to generate the random string
	String chars = "1234567890-=!@#$%^&*()_+qwertyuiop[]\\QWERTYUIOP{}|asdfghjkl;'ASDFGHJKL:\"zxcvbnm,./ZXCVBNM<>?";
  	// Loop based on the requested size
  	for (int i = 0; i < size; i++) {
      	// Add a random char from the chars string to the rand string
		rand += chars.toCharArray()[new Random().nextInt(chars.length())];
	}
  	// Return the random string
	return rand;
}

Popularity 9/10 Helpfulness 5/10 Language java

Source: Grepper

Tags: java

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Contributed on May 28 2021

lavaflowglow

0 Answers Avg Quality 2/10

java random string

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protected String getSaltString() {
        String SALTCHARS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
        StringBuilder salt = new StringBuilder();
        Random rnd = new Random();
        while (salt.length() < 18) { // length of the random string.
            int index = (int) (rnd.nextFloat() * SALTCHARS.length());
            salt.append(SALTCHARS.charAt(index));
        }
        String saltStr = salt.toString();
        return saltStr;

    }

Popularity 9/10 Helpfulness 5/10 Language java

Source: w3programmers.org

Tags: java

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Contributed on Mar 24 2022

Difficult Dragonfly

0 Answers Avg Quality 2/10

java generate random string and number

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import java.util.Random;

public class passGen{
    // Version 1.0
    private static final String dCase = "abcdefghijklmnopqrstuvwxyz";
    private static final String uCase = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    private static final String sChar = "!@#$%^&*";
    private static final String intChar = "0123456789";
    private static Random r = new Random();
    private static StringBuilder pass = new StringBuilder();

    public static void main (String[] args) {
        System.out.println ("Generating pass...");
        while (pass.length () != 16){
            int rPick = r.nextInt(4);
            if (rPick == 0){
                int spot = r.nextInt(26);
                pass.append(dCase.charAt(spot));
            } else if (rPick == 1) {
                int spot = r.nextInt(26);
                pass.append(uCase.charAt(spot));
            } else if (rPick == 2) {
                int spot = r.nextInt(8);
                pass.append(sChar.charAt(spot));
            } else {
                int spot = r.nextInt(10);
                pass.append(intChar.charAt(spot));
            }
        }
        System.out.println ("Generated Pass: " + pass.toString());
    }
}

Popularity 9/10 Helpfulness 2/10 Language java

Source: stackoverflow.com

Tags: generate generat

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Contributed on Feb 26 2022

Restu Wahyu Saputra

0 Answers Avg Quality 2/10

java generate random string and number

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-2

// "0123456789" + "ABCDE...Z"
String validCharacters = $('0', '9').join() + $('A', 'Z').join();

String randomString(int length) {
    return $(validCharacters).shuffle().slice(length).toString();
}

@Test
public void buildFiveRandomStrings() {
    for (int i : $(5)) {
        System.out.println(randomString(12));
    }
}

Popularity 9/10 Helpfulness 1/10 Language java

Source: stackoverflow.com

Tags: generate generat

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Contributed on Feb 26 2022

Restu Wahyu Saputra

0 Answers Avg Quality 2/10

java random String

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