without JSON.parse(JSON.stringify(obj));

Plain Parrot answered on September 3, 2023 Popularity 8/10 Helpfulness 1/10

answer without JSON.parse(JSON.stringify(obj));

without JSON.parse(JSON.stringify(obj));

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function deepCopy(obj) {
  if (obj === null || typeof obj !== 'object') {
    return obj; // Return primitive values as is
  }

  if (Array.isArray(obj)) {
    const newArray = [];
    for (let i = 0; i < obj.length; i++) {
      newArray[i] = deepCopy(obj[i]);
    }
    return newArray;
  }

  const newObj = {};
  for (const key in obj) {
    if (obj.hasOwnProperty(key)) {
      newObj[key] = deepCopy(obj[key]);
    }
  }

  return newObj;
}

// Example usage:
const originalObj = { a: 1, b: { c: 2 } };
const copiedObj = deepCopy(originalObj);

console.log(copiedObj); // Output: { a: 1, b: { c: 2 } }

Popularity 8/10 Helpfulness 1/10 Language javascript

Source: chat.openai.com

Tags: javascript

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Contributed on Sep 03 2023

Plain Parrot

0 Answers Avg Quality 2/10

without JSON.parse(JSON.stringify(obj));

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