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invalid literal for int() with base 10

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YOU.com answered on September 8, 2021 Popularity 10/10 Helpfulness 1/10

answer invalid literal for int() with base 10

related invalid literal for int() with base 10 in python

related invalid literal for int() with base 10 python

related valueerror: invalid literal for int() with base 10: 'id'

related valueerror: invalid literal for int() with base 10: '' pandas

invalid literal for int() with base 10

Comment

try:
    integer_value = int("some_invalid_value")
    # Further code that relies on the converted integer value goes here
    print("Converted integer:", integer_value)
except ValueError:
    print("Invalid literal for int() with base 10")

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

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invalid literal for int() with base 10 in python

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coffee_bags_as_int = int(float(coffee_bags))

Popularity 10/10 Helpfulness 2/10 Language python

Source: careerkarma.com

Tags: base

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Contributed on Feb 21 2023

Sanchit Sanyam

0 Answers Avg Quality 2/10

invalid literal for int() with base 10 in python

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Enter how many coffee bags are left: 7.4
Traceback (most recent call last):
  File "main.py", line 3, in <module>
	coffee_bags_as_int = int(coffee_bags)
ValueError: invalid literal for int() with base 10: '7.4'

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Source: careerkarma.com

Tags: base

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Contributed on Feb 21 2023

Sanchit Sanyam

0 Answers Avg Quality 2/10

invalid literal for int() with base 10 in python

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coffee_bags_as_int = int(coffee_bags)

if coffee_bags_as_int > 10:
	print("You have enough coffee bags.")
else:
	print("You do not have enough coffee bags.")

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Source: careerkarma.com

Tags: base

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Contributed on Feb 21 2023

Sanchit Sanyam

0 Answers Avg Quality 2/10

invalid literal for int() with base 10 python

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#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

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Source: itsmycode.com

Tags: base python

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Contributed on Sep 08 2021

Grotesque Gnu

0 Answers Avg Quality 2/10

valueerror: invalid literal for int() with base 10: 'id'

Comment

#another way is to check if the entered number isdigit()
#that way you will ensure unhandled exception incase of erroneus data

number= input("What is your weight:")
if number.isdigit():
    kilos=int(float(number))
    print ("The weight of the person is:" + str(kilos))
else:
    print("Error - Please enter a proper weight")

Popularity 1/10 Helpfulness 1/10 Language python

Source: itsmycode.com

Tags: base python

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Contributed on Sep 08 2021

Grotesque Gnu

0 Answers Avg Quality 2/10

valueerror: invalid literal for int() with base 10: '' pandas

Comment

// You can't put a string value  into an INT, you either need to convert it (if  you're string is composed of and number)
// Or you need to change the variable content

// How  to convert string to  int ? 

yourVariable = int(stringVariable)

// Convert int to string

yourVariable = str(intVariable)

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Source: Grepper

Tags: base

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Contributed on Jun 18 2022

Victorious Vole

0 Answers Avg Quality 2/10

invalid literal for int() with base 10

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invalid literal for int() with base 10

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invalid literal for int() with base 10 in python

invalid literal for int() with base 10 in python

invalid literal for int() with base 10 in python

invalid literal for int() with base 10 python

valueerror: invalid literal for int() with base 10: 'id'

valueerror: invalid literal for int() with base 10: '' pandas

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