non repeating numbers leetcode

YOU.com answered on September 12, 2023 Popularity 7/10 Helpfulness 1/10

answer non repeating numbers leetcode

non repeating numbers leetcode

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def find_non_repeating_numbers(nums):
    frequency = {}
    
    for num in nums:
        frequency[num] = frequency.get(num, 0) + 1
        
    non_repeating_nums = []
    
    for num in nums:
        if frequency[num] == 1:
            non_repeating_nums.append(num)
    
    return non_repeating_nums

# Example usage:
nums = [1, 1, 2, 3, 4, 4, 5]
result = find_non_repeating_numbers(nums)

print(result)  # Output: [2, 3, 5]

Popularity 7/10 Helpfulness 1/10 Language python

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

non repeating numbers leetcode

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