# Given concentration of sulfuric acid solution
concentration = 1.0 # Assume 1.0 Molar
# Calculate the number of moles of H+ ions
moles_H = concentration * 2 # Sulfuric acid dissociates into 2 H+ ions
# Calculate the volume of the solution (optional)
volume = 100 # Assume 100 mL
# Convert the volume to liters
volume_liter = volume / 1000 # 1000 mL = 1 L
# Calculate the molarity of the H+ ions (optional)
molarity_H = moles_H / volume_liter
# Calculate the pH using the negative logarithm of the molarity
pH = -1 * log10(molarity_H)
print(f"The pH of a {concentration} M sulfuric acid solution is approximately {pH:.2f}")