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import java.util.Scanner;
class SumOfArray{
public static void main(String[] args){
Scanner in = new Scanner(System.in);
System.out.println("Enter the size of array ::: ");
int n = in.nextInt();
int[] arr = new int[n];
System.out.print("Enter the elements in the array ::: ");
for( int i = 0; i < n; i++){
arr[i] = in.nextInt();
}
int sum = 0;
for( int i = 0; i < n; i++){
sum = sum + arr[i];
}
System.out.println("The sum of elements of array ::: "+sum);
}
}
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let arr = [2, 4, 1, 3, 5];
let result = 0;
for (let i = 0; i < arr.length; i++) {
result += arr[i];
}
console.log(result); // 15
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// If you do not want to use array.reduece you can itereate through the array and then get the solution.
const getSum = (arr)=>{
let sum = 0;
for(key of arr){
sum += key
}
return sum
}
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const sum = [1, 2, 3].reduce((partialSum, a) => partialSum + a, 0);
console.log(sum); // 6
Run code snippet
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const sum = (args) => args.reduce((a, b) => a + b, 0);
console.log(sum(1,2,3)); // returns 6
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console.log(
[1,2,3].reduce(function(acc, val) { return acc + val; })
)
console.log(
[].reduce(function(acc, val) { return acc + val; }, 0)
)
Run code snippetHide results
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console.log(
[1,2,3].reduce(function(acc, val) { return acc + val; })
)
console.log(
[].reduce(function(acc, val) { return acc + val; }, 0)
)
Run code snippetHide results
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console.log(
[1,2,3].reduce(function(acc, val) { return acc + val; })
)
console.log(
[].reduce(function(acc, val) { return acc + val; }, 0)
)
Run code snippetHide results