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ip address validation

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Sakhumuzi Khuzwayo answered on August 3, 2020 Popularity 7/10 Helpfulness 2/10

answer ip address validation

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ip address validation

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import java.util.Scanner;

class MyRegex {
    // Define the regular expression pattern for a valid IP address
    String pattern = "^(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$";
}

class Solution {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNext()) {
            String IP = in.next();
            System.out.println(IP.matches(new MyRegex().pattern));
        }
    }
}

Popularity 7/10 Helpfulness 2/10 Language java

Source: chat.openai.com

Tags: ip-address java validation

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Contributed on Sep 29 2023

Sakhumuzi Khuzwayo

0 Answers Avg Quality 2/10

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validate ip address

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function valid_ip(ipString) {
    if (!ipString || typeof ipString !== 'string') {
        return false;
    }

    const splitValues = ipString.split('.');
    if (splitValues.length !== 4) {
        return false;
    }

    for (let i = 0; i < splitValues.length; i++) {
        const tempForParsing = parseInt(splitValues[i], 10);
        if (isNaN(tempForParsing) || tempForParsing < 0 || tempForParsing > 255) {
            return false;
        }
    }

    return true;
}

// Test IP here
const result = valid_ip("192.0.2.146");
console.log(result);

Popularity 9/10 Helpfulness 5/10 Language javascript

Source: Grepper

Tags: ip-address i

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Contributed on Mar 17 2023

Adam, the developer

0 Answers Avg Quality 2/10

Validate IP Address

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try:
            if len(IP.split('.')) == 4:
                print(IP)
                if all([bool(1) if(str(int(s)) == s and 0 <= int(s) <= 255) else bool(0) for s in IP.split('.')]):
                    return "IPv4"
            if len(IP.split(':')) == 8:
                if all([bool(1) if(len(s) <= 4 and int(s, 16) >= 0) else bool(0) for s in IP.split(':')]):
                    return "IPv6"
        except:
            return "Neither"
        return "Neither"

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: ip-address i

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Contributed on Aug 03 2020

Happy Hawk

0 Answers Avg Quality 2/10

ip address validation

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