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syntaxerror: unexpected token u in json at position 0 at json.parse

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Gavin Dennett answered on January 28, 2022 Popularity 7/10 Helpfulness 1/10

answer syntaxerror: unexpected token u in json at position 0 at json.parse

related Unexpected token a in JSON at position

related json parse cause Unexpected token in JSON at position 550

related Unexpected token W in JSON at position 0

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related Unexpected token W in JSON at position 0

related unexpected token o in json at position 1

related Unexpected token W in JSON at position 0

related syntaxerror: unexpected token f in json at position 0

related syntaxerror: unexpected token p in json at position 0 at json.parse (<anonymous>) at xmlhttprequest.onload

syntaxerror: unexpected token u in json at position 0 at json.parse

Comment

 "SyntaxError: Unexpected token u in JSON at position 0" usually indicates that there is a problem with the JSON data being parsed.

The "u" token is not a valid JSON token, so it's likely that the JSON data is corrupted or not properly formatted.

Here are some solutions:

Check the JSON data to ensure it's properly formatted and there are no unnecessary characters at the beginning of the string.

Make sure the data being passed to JSON.parse() is a string, as JSON.parse() expects a string argument.

If you're reading the JSON data from a file or network request, ensure that the encoding is correct and there are no byte order marks (BOM) or other invisible characters causing issues.

Popularity 7/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript json position unexpected-token

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Contributed on Mar 25 2024

Gavin Dennett

0 Answers Avg Quality 2/10

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Unexpected token a in JSON at position

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JSON.parse(JSON.stringify(userData))

Popularity 10/10 Helpfulness 5/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on May 07 2022

Yohana Galusi

0 Answers Avg Quality 2/10

json parse cause Unexpected token in JSON at position 550

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// preserve newlines, etc - use valid JSON
s = s.replace(/\\n/g, "\\n")  
               .replace(/\\'/g, "\\'")
               .replace(/\\"/g, '\\"')
               .replace(/\\&/g, "\\&")
               .replace(/\\r/g, "\\r")
               .replace(/\\t/g, "\\t")
               .replace(/\\b/g, "\\b")
               .replace(/\\f/g, "\\f");
// remove non-printable and other non-valid JSON chars
s = s.replace(/[\u0000-\u0019]+/g,""); 
var o = JSON.parse(s);

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on Jan 28 2022

Clean Cod

0 Answers Avg Quality 2/10

Unexpected token W in JSON at position 0

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Unexpected token W in JSON at position 0

It's because a simple string (plain text) is returned as the response. The text is not a valid JSON. So when you try to do res.json(), it calls JSON.parse(data). Try and do it with the string you provided, and you will get the same error.

use res.text() instead of res.json()

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on May 16 2022

aus ogola

0 Answers Avg Quality 2/10

unhandled rejection (syntaxerror): unexpected token u in json at position 0

Comment

Caused by malformed JSON

Popularity 9/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Oct 10 2022

The Codesmith

0 Answers Avg Quality 2/10

Unexpected token W in JSON at position 0

Comment

Unexpected token W in JSON at position 0

It's because a simple string (plain text) is returned as the response. The text is not a valid JSON. So when you try to do res.json(), it calls JSON.parse(data). Try and do it with the string you provided, and you will get the same error.

use res.text() instead of res.json()

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on May 16 2022

aus ogola

0 Answers Avg Quality 2/10

unexpected token o in json at position 1

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try {
  const jsonString = '{"name": "John", "age": 30}';  // Replace with your JSON string

  const jsonObject = JSON.parse(jsonString);
  console.log(jsonObject);
} catch (error) {
  if (error instanceof SyntaxError) {
    // Handle the syntax error
    console.log("Invalid JSON object. Please check the syntax.");
    console.log("Error message:", error.message);
    console.log("Error occurred at position:", error.at);
  } else {
    // Handle other errors
    console.log("An error occurred:", error);
  }
}

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

Unexpected token W in JSON at position 0

Comment

Unexpected token W in JSON at position 0

It's because a simple string (plain text) is returned as the response. The text is not a valid JSON. So when you try to do res.json(), it calls JSON.parse(data). Try and do it with the string you provided, and you will get the same error.

use res.text() instead of res.json()

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: stackoverflow.com

Tags: javascript j

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Contributed on May 16 2022

aus ogola

0 Answers Avg Quality 2/10

syntaxerror: unexpected token f in json at position 0

Comment

Check out JSON syntax. https://jsonlint.com/

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Jun 02 2022

CharllierJr

0 Answers Avg Quality 2/10

syntaxerror: unexpected token p in json at position 0 at json.parse (<anonymous>) at xmlhttprequest.onload

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mEYEcrosoft

Popularity 2/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript json position unexpected-token

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Contributed on Mar 17 2024

Cloudy Caterpillar

0 Answers Avg Quality 2/10

syntaxerror: unexpected token u in json at position 0 at json.parse

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