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public void ReverseArray(int[] array, int minLength, int maxLength)
{
array = new int[maxLength - (minLength - 1)]; // if the array doesn't start at 0
for (int i = 0; i < array.Length; i++)
{
array[i] = maxLength - i;
}
}
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const numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
const reverseNumbers = numbers.reverse();
console.log(reverseNumbers);
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int[] xr = {1, 2, 3, 4, 5};
System.out.print("[");
for (int i = xr.length - 1; i >= 0; i--) {
System.out.print(xr[i] + ", ");
}
System.out.println("\b\b]");
}
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function reversArray(){
for (let i = 0; i < arr.length; i++) {
for (let j = i + 1; j < arr.length; j++) {
let c, a, b;
b = arr[i];
arr[i] = arr[j];
arr[j] = b;
}
}console.log(arr);
}
let arr = [1, 12, 15, 16, 78, 89, 53 ,'hi'];
reversArray(arr);
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// reverse array elements in javascript
const arr = ["first", "second", "third"];
arr.reverse(); // Mutates the array
console.log(arr); // ["third", "second", "first"]
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const reverseArray = (arr)=>{
for (let v = arr.length ; v > 0 ; v--) {
return arr[v];
}
}
//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)