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create fizz buzz code with python

Msh Bljr Ngoding answered on December 31, 2020 Popularity 1/10 Helpfulness 1/10

answer create fizz buzz code with python

related fizz buzz python

create fizz buzz code with python

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def fizz_buzz(n):
    for i in range(1, n + 1):
        if i % 3 == 0 and i % 5 == 0:
            print("FizzBuzz")
        elif i % 3 == 0:
            print("Fizz")
        elif i % 5 == 0:
            print("Buzz")
        else:
            print(i)

# Example usage masih belajar ngoding
fizz_buzz(100)

Popularity 1/10 Helpfulness 1/10 Language python

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Tags: buzz python

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Contributed on Jul 16 2024

Msh Bljr Ngoding

0 Answers Avg Quality 2/10

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fizz buzz python

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def fizzBuzz(n):
    # Write your code here
    for i in range(1,a):
        if(i%3==0 and i%5!=0):
            print("Fizz")
        elif(i%5==0 and i%3!=0):
            print("Buzz")
        elif(i%5==0 and i%3==0):
            print(i)
a = int(input("enter the no"))
fizzBuzz(a)

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Tags: buzz python

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Contributed on Jun 16 2021

Fierce Fowl

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fizz buzz python

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output = ""

for i in range(1, 101):
 
    if (i % 3 == 0):
        output += "Fizz"
    
    if (i % 5 == 0):
        output += "Buzz"
    
    elif (i % 3 != 0): 
        output += str(i)
    
    output += "\n" # Add a new line at the end of the output 

print(output)

Popularity 9/10 Helpfulness 1/10 Language python

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Tags: python buzz

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Contributed on Nov 06 2021

FriedOxygen

0 Answers Avg Quality 2/10

fizz buzz python

Comments(1)

-1

fizz = 3
buzz = 5
fizzbuzz = fizz * buzz

for i in range(100):
  if i % fizzbuzz == o:
    print('fizzbuzz')
   elif i % fizz == 0:
    print('fizz')
   elif i % buzz == 0: 
    print('buzz')
   else:
    print(i)

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Tags: buzz python

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Contributed on Jul 28 2021

Rich Ratel

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fizz buzz python

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# changeable game of fizz buzz (all you have to change is n and D
# to add or alter the game.
# No adding or changing if/else required to include bizz at 7 or fuzz at 11
# just insert it into the dictionary. (you could easily make a function out of this)

n = 100
D = {3: 'fizz',
     5: 'buzz'}
for x in range(1, n+1):         # makes a range as big as we like
    out = ''
    for k, v in D.items():      # compares each in range with each key in dictionary
        if x % k == 0:
            out += v            # then attaches the associated word onto the output
    if not out:
        out = x                 # if the output is still empty, i.e. no listed factors
    print(out, end=' ')         # the unchanged number becomes the output

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Tags: buzz python

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Contributed on Dec 31 2020

Great Snakes!

0 Answers Avg Quality 2/10

create fizz buzz code with python

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