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sortig number c#

HImel answered on July 26, 2024 Popularity 3/10 Helpfulness 1/10

answer sortig number c#

sortig number c#

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//There are functons to do this faster, but this is a manual approch

using System;

namespace myNamespace
{

        class MyClassTwo 
    {
        public static void Main(string[] args)
        {
            int[] RandomNumbers = { 666,777,444,555,222,333,999,111,888 };
            int[] RandomNumbersTwo = { 666,777,444,555,222,333,999,111,888 };

            
            System.Console.WriteLine("----------------------------------------");
            System.Console.WriteLine("----------   Selection  Sort   ---------");
            System.Console.WriteLine("----------------------------------------");

            for (int j = 0; j < RandomNumbers.Length; j++)
            {
                for (int i = j; i < RandomNumbers.Length; i++)
                {
                    if(RandomNumbers[i] < RandomNumbers[j])
                    {
                        int x = RandomNumbers[j];
                        int y = RandomNumbers[i];

                        RandomNumbers[j] = y;
                        RandomNumbers[i] = x; 
                    }
                }

                for (int i = 0; i < RandomNumbers.Length; i++)
                {
                    System.Console.Write(RandomNumbers[i] + " ");
                }
                Console.WriteLine();
            }

            
            System.Console.WriteLine("----------------------------------------");
            System.Console.WriteLine("----------   Bubble Sort   -------------");
            System.Console.WriteLine("----------------------------------------");


            for (int k = 0; k < RandomNumbersTwo.Length - 1; k++)
            {   
                for (int j = 0; j < RandomNumbersTwo.Length - 1; j++)
                {
                    if(RandomNumbersTwo[j] > RandomNumbersTwo[j+1])
                    {
                        int x = RandomNumbersTwo[j];
                        int y = RandomNumbersTwo[j+1];

                        RandomNumbersTwo[j] = y;
                        RandomNumbersTwo[j+1] = x;
                    }

                }
                
                for (int i = 0; i < RandomNumbersTwo.Length; i++)
                {
                    System.Console.Write(RandomNumbersTwo[i] + " ");
                }
                Console.WriteLine();
            }

        
        }

    }

}

Popularity 3/10 Helpfulness 1/10 Language csharp

Source: Grepper

Tags: c#

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Contributed on Jul 26 2024

HImel

0 Answers Avg Quality 2/10

sortig number c#

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