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java.net.urisyntaxexception: illegal character in opaque part at index 2

SaiKumar answered on August 19, 2024 Popularity 1/10 Helpfulness 1/10

answer java.net.urisyntaxexception: illegal character in opaque part at index 2

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java.net.urisyntaxexception: illegal character in opaque part at index 2

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import java.net.URI;
import java.net.URISyntaxException;

public class URITest {
    public static void main(String[] args) {
        try {
            URI uri = new URI("http://example.com/foo%20bar"); // Correctly encoded URI
            System.out.println("Valid URI: " + uri);
        } catch (URISyntaxException e) {
            System.err.println("URISyntaxException: " + e.getMessage());
        }
    }
}

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Source: nareshit.com

Tags: character whatever

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Contributed on Aug 19 2024

SaiKumar

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java.net.urisyntaxexception: illegal character in opaque part

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The java.net.URISyntaxException: Illegal character in opaque part error occurs when a URL string contains characters that are not valid in certain parts of the URL. This often happens when special characters (like spaces, @, #, etc.) are not properly encoded.

Solution:

Ensure the URL is correctly formatted and encoded.
Use URLEncoder.encode() to encode special characters in query parameters or path segments.
Check for spaces or illegal characters and replace them with %20 or other appropriate encodings.

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Source: nareshit.com

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Contributed on Aug 20 2024

Nareshit

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java.net.urisyntaxexception: illegal character in opaque part at index 2

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