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how to create new reactnative project 2024

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Sher Muhammad answered on May 13, 2020 Popularity 3/10 Helpfulness 1/10

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how to create new reactnative project 2024

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npx @react-native-community/cli@latest init TestApp

Popularity 3/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript project react-native

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Contributed on Oct 30 2024

Sher Muhammad

0 Answers Avg Quality 2/10

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how to start a new react native project

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npx create-react-native-app NAME

Popularity 10/10 Helpfulness 7/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Jun 14 2021

Cautious Cod

0 Answers Avg Quality 2/10

how to create a new react native project

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$ npx react-native init firstapp

Popularity 10/10 Helpfulness 7/10 Language javascript

Source: www.techiediaries.com

Tags: javascript j

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Contributed on May 13 2020

Encouraging Eel

0 Answers Avg Quality 2/10

create react native project

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$ npx react-native init firstapp

Popularity 10/10 Helpfulness 5/10 Language javascript

Source: www.techiediaries.com

Tags: javascript j

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Contributed on Jul 15 2022

Ashamed Ant

0 Answers Avg Quality 2/10

create react native project

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npx react-native@latest init AwesomeProject

Popularity 9/10 Helpfulness 5/10 Language javascript

Source: techhelpbd.com

Tags: javascript j

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Contributed on Apr 19 2024

Kazi Mahbubur Rahman

0 Answers Avg Quality 2/10

quick sort

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function swap(arr, leftIndex, rightIndex){
  // swap 2 elements in the array
    var temp = arr[leftIndex];
    arr[leftIndex] = arr[rightIndex];
    arr[rightIndex] = temp;
}
function partition(arr, left, right) {
    var pivot   = arr[Math.floor((right + left) / 2)], //middle element
        i       = left, //left pointer
        j       = right; //right pointer
    while (i <= j) { // while left pointer is smaller than right pointer
        while (arr[i] < pivot) { // move the left pointer to the right
            i++;
        }
        while (arr[j] > pivot) { // move the right pointer to the left
            j--;
        }
        if (i <= j) { //left pointer smaller or equal to right pointer
            swap(arr, i, j); //sawpping two elements
            i++;
            j--;
        }
    }
    return i;
}
// run as quickSort(array, 0, array.length - 1);
function quickSort(arr, left, right) {
    var index;
    if (arr.length > 1) {
        index = partition(arr, left, right); //index returned from partition
        if (left < index - 1) { //more elements on the left side of the pivot
            quickSort(arr, left, index - 1);
        }
        if (index < right) { //more elements on the right side of the pivot
            quickSort(arr, index, right);
        }
    }
    return arr;
}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: sorting-algorithms.me

Tags: javascript j

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Contributed on Sep 13 2022

katanton reckless

0 Answers Avg Quality 2/10

quick sort

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#https://github.com/paulnegz/sorts-py/blob/main/sort.py
def quick_sort(array :list)->list:
    def _quick_sort(array :list)->list:
        if len(array)<=1: return array
        
        pivot, is_bigger = array.pop(), lambda x: x>pivot
        left_partition = _quick_sort([x for x in array if not is_bigger(x)])
        right_partition = _quick_sort([x for x in array if is_bigger(x)])
        return [*left_partition, pivot, *right_partition]
    return _quick_sort(array)
  
arr = [7, 2, 4, 0, 1, 5, 8, 3, 2, 0]
print(quick_sort(arr)) # [0, 0, 1, 2, 2, 3, 4, 5, 7, 8]

Popularity 10/10 Helpfulness 2/10 Language python

Source: github.com

Tags: whatever whateve

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Contributed on Jun 25 2023

Paul Negedu

0 Answers Avg Quality 2/10

react native new project

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npx @react-native-community/cli init PrOjEcTnAmE

Popularity 7/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript new-project new-projec

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Contributed on Oct 22 2024

Harpreet Singh - xiacom

0 Answers Avg Quality 2/10

quick sort

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  static void swap(int[] arr, int i, int j) {
    int temp = arr[i];
    arr[i] = arr[j];
    arr[j] = temp;
  }  
  
  static int partition(int[] arr, int low, int high) { 
    
    int pivot = arr[high]; 
    // Index of smaller element and
    // indicates the right position
    // of pivot found so far
    int i = (low - 1); 
  
    for(int j = low; j <= high - 1; j++) {
      // If current element is smaller 
      // than the pivot
      if (arr[j] < pivot) {
        // Increment index of 
        // smaller element
        i++; 
        swap(arr, i, j);
      }
    }
    swap(arr, i + 1, high);
    return (i + 1);
  }
  
  static void quickSort(int[] arr, int low, int high) {
      if (low < high) {
          // pi is partitioning index, arr[p]
          // is now at right place 
          int pi = partition(arr, low, high);

          // Separately sort elements before
          // partition and after partition
          quickSort(arr, low, pi - 1);
          quickSort(arr, pi + 1, high);
      }
  }

Popularity 10/10 Helpfulness 2/10 Language java

Source: Grepper

Tags: function functio

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Contributed on Sep 14 2022

Inexpensive Ibex

0 Answers Avg Quality 2/10

quick sort

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def quicksort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    return quicksort(left) + middle + quicksort(right)

print(quicksort([3,6,8,10,1,2,1]))
# Prints "[1, 1, 2, 3, 6, 8, 10]"

Popularity 10/10 Helpfulness 2/10 Language whatever

Source: cs231n.github.io

Tags: whatever whateve

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Contributed on Feb 04 2022

Purple Team

0 Answers Avg Quality 2/10

react native new project

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expo init <project-name

Popularity 10/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Oct 11 2022

CodeNameNinja

0 Answers Avg Quality 2/10

how to create new reactnative project 2024

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