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sort a dictionary by value then key

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SuperUnknown Python answered on November 27, 2019 Popularity 10/10 Helpfulness 3/10

answer sort a dictionary by value then key

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sort a dictionary by value then key

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d = {'apple': 2, 'banana': 3, 'almond':2 , 'beetroot': 3, 'peach': 4}
[v[0] for v in sorted(d.items(), key=lambda kv: (-kv[1], kv[0]))]

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Source: stackoverflow.com

Tags: dictionary key python

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Contributed on Mar 06 2021

SuperUnknown Python

0 Answers Avg Quality 2/10

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python sort a dictionary by values

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x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Contributed on Jul 12 2021

Clear Camel

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python - sort dictionary by value

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d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

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Source: stackoverflow.com

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Contributed on Feb 25 2021

Andrea Perlato

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how to sort a dictionary by value in python

Comment

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

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Contributed on Nov 27 2019

Mobile Star

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how to sort dictionary in python by value

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# your dictionary
a = {'a':4, 'c':5, 'b':3, 'd':0}

# sort x by keys
a_keys = dict(sorted(a.items(),key=lambda x:x[0],reverse = False)) # ascending order
# output: {'a': 4, 'b': 3, 'c': 5, 'd': 0}

# # sort x by values
a_values = dict(sorted(a.items(),key=lambda x:x[1],reverse = False)) # ascending order
# output: {'d': 0, 'b': 3, 'a': 4, 'c': 5}

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Contributed on Aug 24 2021

Darkstar

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sort dict by value

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x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Source: stackoverflow.com

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Contributed on Apr 22 2020

Enchanting Elephant

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sort dict by value

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dict(sorted(x.items(), key=lambda item: item[1]))

Popularity 10/10 Helpfulness 5/10 Language python

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Contributed on Mar 17 2021

Hilarious Hawk

0 Answers Avg Quality 2/10

sort dict by value

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>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Source: stackoverflow.com

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Contributed on Nov 25 2020

Poor Panther

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How to sort a Python dict by value

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# How to sort a Python dict by value
# (== get a representation sorted by value)

>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1}

>>> sorted(xs.items(), key=lambda x: x[1])
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

# Or:

>>> import operator
>>> sorted(xs.items(), key=operator.itemgetter(1))
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

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Contributed on Jul 03 2022

OHIOLee

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python sort dict by value

Comment

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A, key=A.get)}

output:
{4: -20, 1: 2, -1: 4}

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Contributed on Oct 15 2020

IJustWannaHelp

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sort dict by value

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d = {'one':1,'three':3,'five':5,'two':2,'four':4}
a = sorted(d.items(), key=lambda x: x[1])    
print(a)

Popularity 9/10 Helpfulness 4/10 Language python

Source: stackoverflow.com

Tags: python py

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Contributed on Sep 10 2022

Breakable Buffalo

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sort a dictionary by value then key

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