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var arr = [1, 2, 3, 4, 5, 6, 7];
console.log (arr.reverse ());
for (i = 0; i < arr.length / 2; i++) {
var temp = arr[i];
temp =arr[arr.length - 1 - i];
temp = temp;
}
console.log (arr);
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var arr = [34, 234, 567, 4];
print(arr);
var new_arr = arr.reverse();
print(new_arr);
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let arr = [1,2,3]
let newArr = arr.slice().reverse(); //returns a reversed array without modifying the original
console.log(arr, newArr) //[1,2,3] [3,2,1]
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const friends = ["Abir", "Ashik", "Alif", "Alfi", "Shafi", "Kafi"];
const friendsReverse = friends.reverse();
console.log(friendsReverse);
//Output:[ 'Kafi', 'Shafi', 'Alfi', 'Alif', 'Ashik', 'Abir' ]
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const array1 = ['one', 'two', 'three'];
// expected output: "array1:" Array ["one", "two", "three"]
const reversed = array1.reverse();
// expected output: "reversed:" Array ["three", "two", "one"]
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const array1 = ['one', 'two', 'three'];
console.log('array1:', array1);
// expected output: "array1:" Array ["one", "two", "three"]
const reversed = array1.reverse();
console.log('reversed:', reversed);
// expected output: "reversed:" Array ["three", "two", "one"]
// Careful: reverse is destructive -- it changes the original array.
console.log('array1:', array1);
// expected output: "array1:" Array ["three", "two", "one"]
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var arr = ["f", "o", "o", "b", "a", "r"];
arr.reverse();
console.log(arr); // ["r", "a", "b", "o", "o", "f"]
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// reversing an array in javascript is kinda hard. you can't index -1.
// but i can show how you can do it in 4 lines.
var myArray = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
for (var i = myArray.length - 1; i > 0; i -= 1) {
myArray.shift();
myArray.push(i);
}
console.log(myArray); // output: [10, 9, 8, 7, 6, 5, 4, 3, 2, 1]
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#The original array
arr = [11, 22, 33, 44, 55]
print("Array is :",arr)
res = arr[::-1] #reversing using list slicing
print("Resultant new reversed array:",res)