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def is_leap(year): leap = False

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Alex Sylvain Luenga answered on May 7, 2022 Popularity 9/10 Helpfulness 1/10

answer def is_leap(year): leap = False

related leap year condition

def is_leap(year): leap = False

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-1

def is_leap(year):
    leap = False
    if(year%4==0):
        #century year check
        if(year%100==0):
            #century leap year check
            if(year%400==0):
                leap=True
        else:
            leap=True
    return leap

Popularity 9/10 Helpfulness 1/10 Language python

Source: stackoverflow.com

Tags: python

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Contributed on May 07 2022

Alex Sylvain Luenga

0 Answers Avg Quality 2/10

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leap year condition

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function isLeapYear(year){

  if(year % 4 === 0 && year % 100 !== 0 || year % 400 === 0){
    console.log('Leap Year')
  }
  else{
    console.log('Not Leap Year')
  } 
}
isLeapYear(1988)

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: javascript j

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Contributed on Mar 30 2023

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0 Answers Avg Quality 2/10

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def is_leap(year): leap = False

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def is_leap(year): leap = False

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leap year condition

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