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python Program to check if a given year is leap year

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Travinth Dayalaeaswaran answered on March 12, 2022 Popularity 10/10 Helpfulness 5/10

answer python Program to check if a given year is leap year

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python Program to check if a given year is leap year

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# Python program to check leap year or not
def checkYear(year):
    if (year % 4) == 0:
        if (year % 100) == 0:
            if (year % 400) == 0:
                return True
            else:
                return False
        else:
             return True
    else:
        return False
 
# Driver Code
year = 2000
if(checkYear(year)):
    print("Leap Year")
else:
    print("Not a Leap Year")

Popularity 10/10 Helpfulness 5/10 Language python

Source: www.geeksforgeeks.org

Tags: leap-year python

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Contributed on Jul 11 2022

Travinth Dayalaeaswaran

0 Answers Avg Quality 2/10

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Python program to check leap year or not?

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# Python program to check if year is a leap year or not
year = 2004
# To get year (integer input) from the user
# year = int(input("Enter a year: "))
# divided by 100 means century year (ending with 00)
# century year divided by 400 is leap year
if (year % 400 == 0) and (year % 100 == 0):
    print("{0} is a leap year".format(year))
# not divided by 100 means not a century year
# year divided by 4 is a leap year
elif (year % 4 ==0) and (year % 100 != 0):
    print("{0} is a leap year".format(year))
# if not divided by both 400 (century year) and 4 (not century year)
# year is not leap year
else:
    print("{0} is not a leap year".format(year))

Popularity 10/10 Helpfulness 7/10 Language python

Source: Grepper

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Contributed on Mar 12 2022

Sunshine

0 Answers Avg Quality 2/10

how to calculate leap year in python with function

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#Leap year calculator
print('Leap year calculator')
print('>>>')
#=======================================
def is_leap_year(year):
  if (year % 400 == 0) and (year % 100 == 0):
    print(str(year) + " is a leap year".format(year))
    return True
  elif (year % 4 ==0) and (year % 100 == 0):
    print(str(year) + " is a leap year".format(year))
    return True
  else:
    print(str(year) + " is not leap year")
    return False
#=======================================
#input here
#            V  (insert year in ())
is_leap_year(2000)
#=========================================================

Popularity 9/10 Helpfulness 5/10 Language python

Source: Grepper

Tags: function functio

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Contributed on Oct 16 2022

Tapatsatorn Kusolsak

0 Answers Avg Quality 2/10

leap year python

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y = int(input())
if (y % 400 == 0) or (y % 100 != 0 and y %4 == 0):
    print(y,"is leap year.")
else:
    print(y,"isn't leap year.")

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Source: Grepper

Tags: leap-year leap

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Contributed on Aug 31 2022

Excited Earthworm

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check if year is leap python

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# Use calendar.isleap(year)
# https://docs.python.org/3/library/calendar.html#calendar.isleap has more information

import calendar
is_leap = calendar.isleap(2100) # returns False

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Source: Grepper

Tags: python py

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Contributed on Apr 17 2022

CompSciGeek

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python Program to check if a given year is leap year

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python Program to check if a given year is leap year

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Python program to check leap year or not?

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