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deserialize json newtonsoft

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Michael Ross answered on July 6, 2022 Popularity 10/10 Helpfulness 4/10

answer deserialize json newtonsoft

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deserialize json newtonsoft

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        private StoreAndLoadMe DeserializeMe()
        {
            using (StreamReader file = File.OpenText(fileName))
            using (JsonTextReader reader = new JsonTextReader(file))
            {
                JObject obj = (JObject)JToken.ReadFrom(reader);
                return JsonConvert.DeserializeObject<StoreAndLoadMe>(obj.ToString());
            }
        }

        private void SerializeMe(StoreAndLoadMe slm)
        {
            var json = JsonConvert.SerializeObject(slm, Formatting.Indented);
            using (StreamWriter writer  = File.CreateText(fileName))
                writer.Write(json);
        }

// Add Attribute to StoreAndLoadMe class:
    [JsonObject]
    internal class StoreAndLoadMe

Popularity 10/10 Helpfulness 4/10 Language csharp

Source: Grepper

Tags: boolean c# file json line parsing path position unhandled-exception

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Contributed on Aug 26 2022

Michael Ross

0 Answers Avg Quality 2/10

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MyObject obj = JsonConvert.DeserializeObject<MyObject>(json);

Popularity 10/10 Helpfulness 6/10 Language javascript

Source: stackoverflow.com

Tags: c# c

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Contributed on Jul 06 2022

Ill Iguana

0 Answers Avg Quality 2/10

newtonsoft json deserialize custom converter

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public class KeysJsonConverter : JsonConverter
{
    private readonly Type[] _types;

    public KeysJsonConverter(params Type[] types)
    {
        _types = types;
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        JToken t = JToken.FromObject(value);

        if (t.Type != JTokenType.Object)
        {
            t.WriteTo(writer);
        }
        else
        {
            JObject o = (JObject)t;
            IList<string> propertyNames = o.Properties().Select(p => p.Name).ToList();

            o.AddFirst(new JProperty("Keys", new JArray(propertyNames)));

            o.WriteTo(writer);
        }
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        throw new NotImplementedException("Unnecessary because CanRead is false. The type will skip the converter.");
    }

    public override bool CanRead
    {
        get { return false; }
    }

    public override bool CanConvert(Type objectType)
    {
        return _types.Any(t => t == objectType);
    }
}

public class Employee
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public IList<string> Roles { get; set; }
}

Popularity 9/10 Helpfulness 2/10 Language javascript

Source: www.newtonsoft.com

Tags: converter conv

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Contributed on Jan 08 2023

Burak Çelebi

0 Answers Avg Quality 2/10

deserialize json newtonsoft

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