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c# deserialize json

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AB_498 answered on May 2, 2020 Popularity 10/10 Helpfulness 4/10

answer c# deserialize json

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c# deserialize json

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//format(object array): [{},{},{}]
List<Employee> emps = Newtonsoft.Json.JsonConvert.DeserializeObject<List<Employee>>(jsonString);
//format(object): {}
Employee emp = Newtonsoft.Json.JsonConvert.DeserializeObject<Employee>(jsonString);

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Tags: c# json

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Contributed on Dec 10 2022

AB_498

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deserialize json to object c#

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dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);

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Tags: c# c

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Contributed on May 02 2020

Frantic Fly

0 Answers Avg Quality 2/10

.NET JSON: DeserializeAsync

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using System.Text.Json;

namespace DeserializeFromFileAsync
{
    public class WeatherForecast
    {
        public DateTimeOffset Date { get; set; }
        public int TemperatureCelsius { get; set; }
        public string? Summary { get; set; }
    }

    public class Program
    {
        public static async Task Main()
        {
            string fileName = "WeatherForecast.json";
            using FileStream openStream = File.OpenRead(fileName);
            WeatherForecast? weatherForecast = 
                await JsonSerializer.DeserializeAsync<WeatherForecast>(openStream);

            Console.WriteLine($"Date: {weatherForecast?.Date}");
            Console.WriteLine($"TemperatureCelsius: {weatherForecast?.TemperatureCelsius}");
            Console.WriteLine($"Summary: {weatherForecast?.Summary}");
        }
    }
}
// output:
//Date: 8/1/2019 12:00:00 AM -07:00
//TemperatureCelsius: 25
//Summary: Hot

Popularity 9/10 Helpfulness 5/10 Language csharp

Source: learn.microsoft.com

Tags: .net

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Contributed on Nov 25 2022

Arti

0 Answers Avg Quality 2/10

.NET JSON: Deserialize

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using System.Text.Json;

namespace DeserializeFromFile
{
    public class WeatherForecast
    {
        public DateTimeOffset Date { get; set; }
        public int TemperatureCelsius { get; set; }
        public string? Summary { get; set; }
    }

    public class Program
    {
        public static void Main()
        {
            string fileName = "WeatherForecast.json";
            string jsonString = File.ReadAllText(fileName);
            WeatherForecast weatherForecast = JsonSerializer.Deserialize<WeatherForecast>(jsonString)!;

            Console.WriteLine($"Date: {weatherForecast.Date}");
            Console.WriteLine($"TemperatureCelsius: {weatherForecast.TemperatureCelsius}");
            Console.WriteLine($"Summary: {weatherForecast.Summary}");
        }
    }
}
// output:
//Date: 8/1/2019 12:00:00 AM -07:00
//TemperatureCelsius: 25
//Summary: Hot

Popularity 10/10 Helpfulness 4/10 Language csharp

Source: learn.microsoft.com

Tags: .net

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Contributed on Nov 25 2022

Arti

0 Answers Avg Quality 2/10

deserialize json c#

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using System;
using System.Text.Json;

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

public class Program
{
    public static void Main()
    {
        string json = "{\"Name\":\"John\",\"Age\":30}";

        // Deserialize JSON to object
        Person person = JsonSerializer.Deserialize<Person>(json);

        Console.WriteLine("Name: " + person.Name);
        Console.WriteLine("Age: " + person.Age);
    }
}

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Contributed on Sep 11 2023

YOU.com

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c# deserialize json

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