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1043 uri solution c

MD. Yeasine Dewan Shawon answered on June 19, 2022 Popularity 3/10 Helpfulness 1/10

answer 1043 uri solution c

1043 uri solution c

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#include <stdio.h>
int main()
{
    float A, B, C;
    scanf("%f %f %f", &A, &B, &C);
    if (A < B+C && B < A+C && C < B+C){
        printf("Perimetro = %.1f\n",A+B+C);
    }
    else
        printf("Area = %.1f\n",((A+B)*C) / 2);
    return 0;
}

Popularity 3/10 Helpfulness 1/10 Language c

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Contributed on Oct 14 2022

MD. Yeasine Dewan Shawon

0 Answers Avg Quality 2/10

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uri 1045 solution in c

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#include <stdio.h>

int main(){
    double a,b,c;

    scanf("%lf %lf %lf", &a, &b, &c);

    if(a >= (b+c) || b >= (a+c) || c >= (a+b))
         printf("NAO FORMA TRIANGULO\n");
    else if(a*a == (b*b + c*c) || b*b == (a*a + c*c) || c*c == (a*a + b*b))
           printf("TRIANGULO RETANGULO\n");
    else if(a*a > (b*b + c*c) || b*b > (a*a + c*c) || c*c > (a*a + b*b))
           printf("TRIANGULO OBTUSANGULO\n");
    else if(a*a < (b*b + c*c) || b*b < (a*a + c*c) || c*c < (a*a + b*b))
           printf("TRIANGULO ACUTANGULO\n");
    if(a == b && a == c)
            printf("TRIANGULO EQUILATERO\n");
    if((a == b && a != c)  || (a == c && a != b) || (b == c && b != a))
            printf("TRIANGULO ISOSCELES\n");

 return 0;
    
}

Popularity 5/10 Helpfulness 4/10 Language c

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Contributed on Oct 14 2022

MD. Yeasine Dewan Shawon

0 Answers Avg Quality 2/10

1041 uri solution

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//uri problem 1041 || coordinates of a point in python 3.9

inp = input()
x, y = inp.split()
x = float(x)
y = float(y)
if x == 0 and y ==0:
    print("Origem")
elif(x==0):
    print("Eixo Y")
elif(y==0):
    print("Eixo X")
elif x > 0 and y > 0:
    print("Q1")
elif x < 0 and y > 0:
    print("Q2")
elif x < 0 and y < 0:
    print("Q3")
elif x > 0 and y < 0:
    print("Q4")

Popularity 6/10 Helpfulness 1/10 Language python

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Contributed on Jun 19 2022

PointBreak

0 Answers Avg Quality 2/10

1042 uri solution

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#uri 1042 solution || simple sort
x, y, z = map(int,input().split())
arr = [x,y,z]
arr.sort()
print(f"{arr[0]}\n{arr[1]}\n{arr[2]}")
print(f"\n{x}\n{y}\n{z}")

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Contributed on Jun 19 2022

PointBreak

0 Answers Avg Quality 2/10

1043 uri solution

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-2

# 1043 triangle
a, b, c = map(float,input().split())
if a+b > c and b+c > a and a+c > b:
    peri = a+b+c
    print("Perimetro = {:.1f}".format(peri))
else:
    area = ((a+b)/2) *c
    print("Area = {:.1f}".format(area))

Popularity 4/10 Helpfulness 1/10 Language python

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Contributed on Jun 20 2022

PointBreak

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1044 uri solution

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# 1044 Multiples
a, b = map(int,input().split())
if a%b ==0 or b%a == 0:
    print("Sao Multiplos")
else:
    print("Nao sao Multiplos")

Popularity 4/10 Helpfulness 1/10 Language python

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Contributed on Jun 20 2022

PointBreak

0 Answers Avg Quality 2/10

1046 uri solution

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a,b=list(map(int,input().split()))
if(a<b):
    time=b-a
else:
    time=b+24-a
print(f"O JOGO DUROU {time} HORA(S)")

Popularity 5/10 Helpfulness 1/10 Language python

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Contributed on Jun 25 2022

Exuberant Eel

0 Answers Avg Quality 2/10

1045 uri solution

Comment

data = list(map(float, input().split( )))

data.sort(reverse=True) 

a,b,c = data

if a>=b+c:
    print("NAO FORMA TRIANGULO")
elif a**2 == b**2 + c**2:
    print("TRIANGULO RETANGULO")
elif a**2 > b**2 + c**2:
    print("TRIANGULO OBTUSANGULO")
elif a**2 < b**2 + c**2:
    print("TRIANGULO ACUTANGULO")
    
if a==b and a==c and b==a and b==c and c==a and c==b:
    print("TRIANGULO EQUILATERO")
elif a==b or a==c or b==a or b==c or c==a or c==b:
    print("TRIANGULO ISOSCELES")

Popularity 6/10 Helpfulness 1/10 Language python

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Contributed on Jun 25 2022

Exuberant Eel

0 Answers Avg Quality 2/10

1047 uri solution

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a,c,b,d=list(map(int,input().split()))

dif=((b*60)+d)-((a*60)+c)
if(dif<=0):
    dif+=24*60
    
time=dif//60
minute=dif%60
print(f"O JOGO DUROU {time} HORA(S) E {minute} MINUTO(S)")

Popularity 6/10 Helpfulness 1/10 Language python

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Contributed on Jun 25 2022

Exuberant Eel

0 Answers Avg Quality 2/10

uri 1042 solution in c

Comment

#include <stdio.h>
void printInOrder(int a, int b, int c)
{
    int min, mid, max;
    if(a < b && a < c){
        min = a;
        if(b < c){
            mid = b;
            max = c;
        }else{
            mid = c;
            max = b;
        }
    }else if(b < a && b < c){
        min = b;
        if(a < c){
            mid = a;
            max = c;
        }else{
            mid = c;
            max = a;
        }
    }else{
        min = c;
        if(a < b){
            mid = a;
            max = b;
        }else{
            mid = b;
            max = a;
        }
    }
    printf("%d\n%d\n%d\n", min, mid, max);
}
int main()
{
    int a, b, c;
    scanf("%d %d %d", &a, &b, &c);
    printInOrder(a, b, c);
    printf("\n%d\n%d\n%d\n", a, b, c);
    return 0;
}

Popularity 1/10 Helpfulness 1/10 Language c

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Tags: c solution uri

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Contributed on Oct 25 2022

MD. Yeasine Dewan Shawon

0 Answers Avg Quality 2/10

1043 uri solution c

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