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python sort by key

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Abdul Basit answered on February 1, 2021 Popularity 9/10 Helpfulness 3/10

answer python sort by key

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arr = [
    {
    'id' : 1,
    'name' : 'Name 1'
    },
    {
    'id' : 4,
    'name' : 'Name 4'
    },
    {
    'id' : 2,
    'name' : 'Name 2'
    },
    {
    'id' : 3,
    'name' : 'Name 3'
    }
  ]

sorted_array = list(sorted(arr,key=lambda x:x['id']))

Popularity 9/10 Helpfulness 3/10 Language python

Source: Grepper

Tags: key python

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Contributed on Mar 07 2023

Abdul Basit

0 Answers Avg Quality 2/10

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list sort by key python

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>>> student_tuples = [
...     ('john', 'A', 15),
...     ('jane', 'B', 12),
...     ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2])   
# sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

Popularity 10/10 Helpfulness 5/10 Language python

Source: wayhome25.github.io

Tags: key

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Contributed on Feb 01 2021

Angry Alligator

0 Answers Avg Quality 2/10

sort list by key

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# sort list by key
st1 = [ [ 1, 2], [3, 4], [4, 2], [ -1, 3], [ 4, 5], [2, 3]]
st1.sort()
print(st1)					# sort by  1st element [ [ -1, 3 ], [ 1, 2 ], [ 2, 3 ] ...
st1.sort(reverse=True)
print(st1)					# sort decending [ [ 4, 5 ], [ 3, 4], [ 2, 3 ] ...
st1.sort(key=lambda x: x[1])			# sort by 2nd element accending
print(st1)					# [ [ 1, 2 ], [ 4, 2 ], [ -1, 3 ] ...
st1.sort(key=lambda x: x[0] + x[1])		# sort by sum of 1st and 2nd element accending
print(st1)					# [ [ -1, 3 ], [ 1, 2 ], [ 2, 3 ] ...
# lambda undefined function
def sort_func(x) :				# classic way
	return x[0] + x[1]
st1.sort(key=sort_func)
st1.sort(key=lambda x: x[0] + x[1])		# defined function lambda at place

Popularity 9/10 Helpfulness 5/10 Language python

Source: Grepper

Tags: key

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Contributed on Mar 22 2022

Impossible Impala

0 Answers Avg Quality 2/10

python sort array by key

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# sort list by key
st1 = [ [ 1, 2], [3, 4], [4, 2], [ -1, 3], [ 4, 5], [2, 3]]
st1.sort()
print(st1)					# sort by  1st element [ [ -1, 3 ], [ 1, 2 ], [ 2, 3 ] ...
st1.sort(reverse=True)
print(st1)					# sort decending [ [ 4, 5 ], [ 3, 4], [ 2, 3 ] ...
st1.sort(key=lambda x: x[1])			# sort by 2nd element accending
print(st1)					# [ [ 1, 2 ], [ 4, 2 ], [ -1, 3 ] ...
st1.sort(key=lambda x: x[0] + x[1])		# sort by sum of 1st and 2nd element accending
print(st1)					# [ [ -1, 3 ], [ 1, 2 ], [ 2, 3 ] ...
# lambda undefined function
def sort_func(x) :				# classic way
	return x[0] + x[1]
st1.sort(key=sort_func)
st1.sort(key=lambda x: x[0] + x[1])		# defined function lambda at place

Popularity 8/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: key python py

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Contributed on Nov 14 2022

Meng Yuan

0 Answers Avg Quality 2/10

sort key python

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>>> sorted(student_tuples, key=itemgetter(2))
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

Popularity 10/10 Helpfulness 3/10 Language python

Source: docs.python.org

Tags: key

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Contributed on Jul 21 2021

Nikoooo

0 Answers Avg Quality 2/10

sort key python

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>>> student_objects = [
...     Student('john', 'A', 15),
...     Student('jane', 'B', 12),
...     Student('dave', 'B', 10),
... ]
>>> sorted(student_objects, key=lambda student: student.age)   # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

Popularity 10/10 Helpfulness 2/10 Language python

Source: docs.python.org

Tags: key

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Contributed on Jul 21 2021

Nikoooo

0 Answers Avg Quality 2/10

sort key python

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>>> class Student:
...     def __init__(self, name, grade, age):
...         self.name = name
...         self.grade = grade
...         self.age = age
...     def __repr__(self):
...         return repr((self.name, self.grade, self.age))

Popularity 10/10 Helpfulness 1/10 Language python

Source: docs.python.org

Tags: key

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Contributed on Jul 21 2021

Nikoooo

0 Answers Avg Quality 2/10

python sort by key

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