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armstrong number in c++

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Mohammad Amaan Patloo answered on February 3, 2022 Popularity 5/10 Helpfulness 1/10

answer armstrong number in c++

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armstrong number in c++

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#include <iostream>
#include <cmath>
using namespace std;

int main() {
   int num, originalNum, remainder, n = 0;
   float result = 0.0;

   cout << "Enter an integer: ";
   cin >> num;

   originalNum = num;

   // count number of digits
   while (originalNum != 0) {
      originalNum = originalNum/10;
      n++;
   }

   originalNum = num;

   // calculate sum of nth power of digits
   while (originalNum != 0) {
      remainder = originalNum % 10;
      result = result + pow(remainder, n);
      originalNum = originalNum / 10;
   }

   // check if number is Armstrong
   if (result == num)
      cout << num << " is an Armstrong number.";
   else
      cout << num << " is not an Armstrong number.";

   return 0;
}

Popularity 5/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Mar 08 2023

Mohammad Amaan Patloo

0 Answers Avg Quality 2/10

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armstrong number in cpp

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// armstrong or not

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
    int num, temp, i, j, rem, sum=0, power=0;

    cout<< "Enter the number: ";
    cin>> num;

    temp = num;

    for(i=1; temp!=0; i++)
    {
        rem = temp % 10;
        for(j=0; j<10;j++)
        {
            if (rem == j)
                power++;
        }
        temp = temp / 10;
    }

    temp = num;

    for(i=1; temp!=0; i++)
    {
        rem = temp % 10;
        sum = sum + pow(rem, power);
        temp = temp / 10;
    }


    if(sum == num)
        cout<< "armstrong" ;
    else
        cout<< "Not armstrong";

    return 0;
}

Popularity 8/10 Helpfulness 5/10 Language cpp

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Tags: c++

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Contributed on Feb 03 2022

Sleep deprived

0 Answers Avg Quality 2/10

armstrong number in c++

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#include <iostream>
using namespace std;

void armStrongNumber()
{
    int n, remainder, sum = 0, temp;
    cout << "Enter number" << endl;
    cin >> n;
    temp = n;
    while (n > 0)
    {
        remainder = n % 10;
        sum = sum + (remainder * remainder * remainder);
        n = n / 10;
    }
    if (temp == sum)
    {
        cout << temp << " is a Armstrong Number" << endl;
    }
    else
    {
        cout << temp << " is not an Armstrong Number" << endl;
    }
}

void perfectNumbers()
{
    int n, sum = 0, i;
    cout << "Enter number" << endl;
    cin >> n;

    for (i = 1; i < n; i++)
    {
        if (n % i == 0)
        {
            sum = sum + i;
        }
    }
    if (n == sum)
    {
        cout << n << " is a Perfect Number" << endl;
    }
    else
    {
        cout << n << " is not a Perfect Number" << endl;
    }
}
int main()
{

    int x;
    cout << "Enter 1 to calculate perfectNumbers\nEnter 2 to calculate Armstrong numbers" << endl;
    cin >> x;

    
    switch (x)
    {
    case 1:
        perfectNumbers();
        break;
    case 2:
        armStrongNumber();
        break;
    default:
        cout << "You entered wrong input" << endl;
    }
    return 0;
}

Popularity 8/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: perfect c++

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Contributed on Dec 07 2022

Leo Fras

0 Answers Avg Quality 2/10

armstrong number in c++

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